COM pressing＆QUOT; N＆QUOT; -time对象的成员通话 [英] Compressing "n"-time object member call

问题描述

有任何非显性为办法调用成员 N 倍于一个对象？

Is there any non-explicit for way to call a member n times upon an object?

我在想一些的map / reduce /λ的办法，但我不能想出一个办法做到这一点 - 如果可能的话

I was thinking about some map/reduce/lambda approach, but I couldn't figure out a way to do this -- if it's possible.

我想补充的背景下，我使用 BeautifulSoup ，而且我提取HTML表格中的一些元素;我提取一些元素，然后在最后一个。

Just to add context, I'm using BeautifulSoup, and I'm extracting some elements from an html table; I extract some elements, and then, the last one.

因为我有：

# First value
print value.text

# Second value
value = value.nextSibling
print value.text

# Ninth value
for i in xrange(1, 7):
    value = value.nextSibling
print value.text

我想知道是否有任何的λ办法 - 或者别的东西 - 这将允许我这样做：

I was wondering if there's any lambda approach -- or something else -- that would allow me to do this:

# Ninth value
((value = value.nextSibling) for i in xrange(1, 7))
print value.text

PS：没有，任何没有问题与为的办法，但我真的很喜欢单行的解决方案，而这将适合我的code真的很好

P.S.: No, there's no problem whatsoever with the for approach, except I really enjoy one-liner solutions, and this would fit really nice in my code.

推荐答案

我对循环强烈preference，但你的可能的使用减少：

I have a strong preference for the loop, but you could use reduce:

>>> class Foo(object):
...     def __init__(self):
...        self.count = 0
...     def callme(self):
...        self.count += 1
...        return self
... 
>>> a = Foo()
>>> reduce(lambda x,y:x.callme(),range(7),a)
<__main__.Foo object at 0xec390>
>>> a.count
7

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