类型错误，如果link.has_attr（'href“属性）：类型错误：'NoneType'对象不是可调用 [英] Type error if link.has_attr('href'): TypeError: 'NoneType' object is not callable

问题描述

我试图执行以下蟒蛇code

I was trying to execute the following python code

import httplib2
from BeautifulSoup import BeautifulSoup, SoupStrainer

http = httplib2.Http()
status, response = http.request('http://www.nytimes.com')

for link in BeautifulSoup(response, parseOnlyThese=SoupStrainer('a')):
    if link.has_attr('href'):
        print link['href']

编辑：
我改变了code将该

I changed the code to this

for link in BeautifulSoup(response).find_all('a', href=True):
    print link['href']

但仍然得到同样的错误。

But still getting same error

我收到错误

Traceback (most recent call last):
  File "/home/user1/Documents/machinelearning/extract_links.py", line 8, in <module>
    if link.has_attr('href'):
TypeError: 'NoneType' object is not callable

什么是此错误的原因是什么？
我怎样才能解决这个问题？

What is the reason for this error? How can I solve this?

推荐答案

您名单连同无在它返回一串数值。

Your list is returning a bunch of values along with None in it.

您最好使用 find_all（）在这里，在我看来：

You're better off using find_all() here, in my opinion:

for link in BeautifulSoup(response).find_all('a', href=True):
    print link['href']

的 HREF =真只能找到一个的href 值的标签，这样你就不会需要你有条件的。

The href=True will only find a tags with a href value, so you won't need your conditional.

这篇关于类型错误，如果link.has_attr（'href“属性）：类型错误：'NoneType'对象不是可调用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！