字符串搜索返回none或[] [英] string search returns none or []

问题描述

我有我想打开一个特定的地方，搜索特定的名字多个URL，但我才刚刚返回无或[]。

I have several urls that i want to open to a specific place and search for a specific name but I'm only getting None returned or [].

我已搜查，但不能看到一个答案是有关我的code。

I have searched but cannot see an answer that is pertinent to my code.

from bs4 import BeautifulSoup
from urllib import request

webpage = request.urlopen("http://www.dsfire.gov.uk/News/Newsdesk/IncidentsPast7days.cfm?siteCategoryId=3&T1ID=26&T2ID=35")
soup = BeautifulSoup(webpage)
incidents = soup.find(id="CollapsiblePanel1")
Links = []
for line in incidents.find_all('a'):
    Links.append("http://www.dsfire.gov.uk/News/Newsdesk/"+line.get('href'))
n = 0
e = len(Links)
while n < e:
    webpage = request.urlopen(Links[n])
    soup = BeautifulSoup(webpage)
    station =  soup.find(id="IncidentDetailContainer")
    #search string
    print(soup.body.findAll(text='Ashburton'))
    n=n+1

我知道在页面上找到的最后一个环节了。

I know its in the last link found on the page.

在此先感谢您的任何想法或意见

Thanks in advance for any ideas or comments

推荐答案

如果您的输出中是[]只是，这意味着你的输出是一个数组。你必须设置索引，然后=>变量[指数]。

If your ouput is "[]" only, it means your output is an array. You have to set the index then => variable[index].

试试这个

print(soup.body.findAll(text='Ashburton')[0])

...其中将其存储到一个变量第一会更容易：

...where storing it into a variable first would be easier:

search = soup.body.findAll(text='Ashburton')
print(search[0])

这将带给你找到的第一个项目。

This will bring you the first found item.

有关打印找到的所有项目，你可以去

For printing all found items you could go

search = soup.body.findAll(text='Ashburton')
foreach(entry in search)
    print(entry)

请注意这是更pseude- code，而不是工作的例子。我真的不知道beautifulsoap。的

Notice this is more pseude-code instead of a working example. I really dont know beautifulsoap.

这篇关于字符串搜索返回none或[]的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！