在Java中，我可以定义为二进制格式的整型常量？ [英] In Java, can I define an integer constant in binary format?
问题描述
要如何定义一个整数十六进制或八进制常数相似，我可以做的二进制？
Similar to how you can define an integer constant in hexadecimal or octal, can I do it in binary?
我承认这是一个非常简单的（和愚蠢的）问题。我的谷歌搜索都上来了空。
I admit this is a really easy (and stupid) question. My google searches are coming up empty.
推荐答案
所以，用的Java SE 7的发布，二进制记数法标配开箱。语法是相当简单和明显的，如果你有二进制体面的理解：
So, with the release of Java SE 7, binary notation comes standard out of the box. The syntax is quite straight forward and obvious if you have a decent understanding of binary:
byte fourTimesThree = 0b1100;
byte data = 0b0000110011;
short number = 0b111111111111111;
int overflow = 0b10101010101010101010101010101011;
long bow = 0b101010101010101010101010101010111L;
和专门的声明类级变量为二进制的地步，但绝对没有问题，使用二进制表示法初始化静态变量之一：
And specifically on the point of declaring class level variables as binaries, there's absolutely no problem initializing a static variable using binary notation either:
public static final int thingy = 0b0101;
只是要小心不要用太多的数据溢出的数字，否则你会得到一个编译器错误：
Just be careful not to overflow the numbers with too much data, or else you'll get a compiler error:
byte data = 0b1100110011; // Type mismatch: cannot convert from int to byte
现在，如果你真的想获得幻想，你可以在被称为用下划线数字文字Java 7的结合，其他整齐的新功能。看看二进制符号与文字下划线的这些花哨的例子：
Now, if you really want to get fancy, you can combine that other neat new feature in Java 7 known as numeric literals with underscores. Take a look at these fancy examples of binary notation with literal underscores:
int overflow = 0b1010_1010_1010_1010_1010_1010_1010_1011;
long bow = 0b1__01010101__01010101__01010101__01010111L;
现在是不是非常干净的，何况高度可读？
Now isn't that nice and clean, not to mention highly readable?
我从一个小文章，我写了一篇关于在的TheServerSide的话题拉扯了这些code片段。随时检查出来的更多详细信息：
I pulled these code snippets from a little article I wrote about the topic over at TheServerSide. Feel free to check it out for more details:
的Java 7和二进制表示法：掌握OCP Java程序员（OCPJP）考试
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