PHP读取文件的字节数组 [英] PHP read file as an array of bytes

问题描述

我必须使用具有写成二进制整数数组我做了一个for循环在这个阵列，并用这种方法写 JAVA 程序编写的文件

I have a file written using JAVA program which has an array of integers written as binary I made an for loop over this array and write it using this method

public static void writeInt(OutputStream out, int v) throws IOException {
    out.write((v >>> 24) & 0xFF);
    out.write((v >>> 16) & 0xFF);
    out.write((v >>> 8) & 0xFF);
    out.write((v >>> 0) & 0xFF);
}

我询问有关如何读 PHP 。

推荐答案

我相信，code，你要找的是：

I believe the code you are looking for is:

$byteArray = unpack("N*",file_get_contents($filename));

更新：按OP提供工作code

UPDATE: Working code supplied by OP

$filename = "myFile.sav"; 
$handle = fopen($filename, "rb"); 
$fsize = filesize($filename); 
$contents = fread($handle, $fsize); 
$byteArray = unpack("N*",$contents); 
print_r($byteArray); 
for($n = 0; $n < 16; $n++)
{ 
    echo $byteArray [$n].'<br/>'; 
}

这篇关于PHP读取文件的字节数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！