操纵在Python中的二进制数据 [英] Manipulating binary data in Python

问题描述

我打开一个二进制文件，像这样：

I am opening up a binary file like so:

file = open("test/test.x", 'rb')

和在线条列表中读取。每一行看起来有点像：

and reading in lines to a list. Each line looks a little like:

'\xbe\x00\xc8d\xf8d\x08\xe4.\x07~\x03\x9e\x07\xbe\x03\xde\x07\xfe\n'

我有一个很难操纵这些数据。如果我尝试并打印每一行，蟒蛇冻结，并发出蜂鸣噪声（我觉得有一个二进制哔code在某处）。我怎么去安全地使用这些数据？我怎么能相互转换的十六进制数到十进制？

I am having a hard time manipulating this data. If I try and print each line, python freezes, and emits beeping noises (I think there's a binary beep code in there somewhere). How do I go about using this data safely? How can I convert each hex number to decimal?

推荐答案

要打印，你可以做这样的事情：

To print it, you can do something like this:

print repr(data)

有关整件事为十六进制：

For the whole thing as hex:

print data.encode('hex')

对于每个字节的十进制值：

For the decimal value of each byte:

print ' '.join([str(ord(a)) for a in data])

要解压二进制整数，等等。从数据就好像它最初是从C风格的结构来了，看结构模块。

To unpack binary integers, etc. from the data as if it originally came from a C-style struct, look at the struct module.

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