蟒蛇：HTTP与unen codeD二进制数据PUT [英] python: HTTP PUT with unencoded binary data

问题描述

我不能为我的生活弄清楚如何与逐字二进制数据在Python 2.7的标准Python库执行HTTP PUT请求。

I cannot for the life of me figure out how to perform an HTTP PUT request with verbatim binary data in Python 2.7 with the standard Python libraries.

我想我可以用urllib2的做到这一点，但失败了，因为的 urllib2.Request 预计其数据应用程序/ x-WWW的形式urlen codeD 格式。我不想EN code中的二进制数据，我只是想逐字发送出去，包括

I thought I could do it with urllib2, but that fails because urllib2.Request expects its data in application/x-www-form-urlencoded format. I do not want to encode the binary data, I just want to transmit it verbatim, after the headers that include

Content-Type: application/octet-stream
Content-Length: (whatever my binary data length is)

这看起来很简单，但我一直转圈圈，似乎无法弄清楚如何。

This seems so simple, but I keep going round in circles and can't seem to figure out how.

我怎样才能做到这一点？ （除了开辟原始二进制套接字和写入）

How can I do this? (aside from open up a raw binary socket and write to it)

推荐答案

我找到了我的问题。它似乎还有在 urllib2.Request / urllib2.urlopen （） （至少在Python 2.7）

I found out my problem. It seems there is some obscure behavior in urllib2.Request / urllib2.urlopen() (at least in Python 2.7)

的 urllib2.Request（网址，数据，标题）构造似乎期待同类型在其URL和数据参数字符串。

The urllib2.Request(url, data, headers) constructor seems to expect the same type of string in its url and data parameters.

我是从文件读取（）电话给数据参数的原始数据（这在Python 2.7返回时，就在一个'纯'字符串的形式），但我的网址是偶然的Uni code，因为我从返回的Uni code字符串的另一个函数的结果级联的URL的一部分。

I was giving the data parameter raw data from a file read() call (which in Python 2.7 returns it in the form of a 'plain' string), but my url was accidentally Unicode because I concatenated a portion of the URL from the result of another function which returned Unicode strings.

而不是试图垂头丧气网​​址从统一code - >普通字符串，它试图向上转型的数据参数统一code，它给了我一个codeC错误。 （奇怪的是，这种情况发生在 urllib2.urlopen（）函数调用，而不是 urllib2.Request 构造函数）

Rather than trying to "downcast" url from Unicode -> plain strings, it tried to "upcast" the data parameter to Unicode, and it gave me a codec error. (oddly enough, this happens on the urllib2.urlopen() function call, not the urllib2.Request constructor)

当我改变了我的函数调用

When I changed my function call to

# headers contains `{'Content-Type': 'application/octet-stream'}`
r = urllib2.Request(url.encode('utf-8'), data, headers)

它工作得很好。

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