如何读取二进制文件整数和日期 [英] How to read integers and date in binary file
问题描述
我的记录的二进制文件。每个记录的格式如下：
每个记录包含两个整数，车辆和涉及的人数的数量;一个浮点数，严重code;并且包含事故发生之日起的字符串。该日期的格式如下：三个字母月份缩写后跟一个空格，然后是一个月后跟一个逗号的一天，终于在今年可能重新由两位或四位数字psented $ P $
I have a binary file of records. Each record is of the following format: Each record consists of two integers, number of vehicles and number of persons involved; a floating point number, severity code; and a string which contains the date of the accident. This date takes the following form: a three letter month abbreviation followed by a space, then a day of the month followed by a comma, and finally the year which may be represented by a two digit or four digit number.
以下是code.But我没有得到正确的答案。
Following is the code.But I am not getting the proper answer..
我的code：
import java.io.*;
public class BoydBAssignment5_Ver1 {
public static void main(String s[]) {
DataInputStream input1; //you need these two variable for a file
File infile1;
input1 = null;
BoydBAssignment5_Ver1 tfr; //this is your program object
tfr = new BoydBAssignment5_Ver1();
try{ //try for open
infile1 = new File("assign5.data");
input1 = new DataInputStream(new FileInputStream(infile1));
} catch (IOException i){
i.printStackTrace();}
tfr.read_records(input1);
try { //try for close
input1.close();
} catch (IOException i) {
System.out.println("error in close");
}
}
private void read_records(DataInputStream is2) {
int totalVehicles=0,totalPersons=0;
int numVehicles;
int numPeople;
char ch;
try { //try for read
while(true) {
numVehicles=is2.readInt();
if(numVehicles==0)
break;
totalVehicles+=numVehicles;
System.out.print("\n"+numVehicles+"\t");
numPeople=is2.readInt();
if(numPeople==0)
break;
totalPersons+=numPeople;
System.out.print(numPeople+"\t");
System.out.print(is2.readDouble()+"\t");
/*System.out.print(is2.readLine()+"\n");
for(int k=0;k<4;k++)
{
is2.readByte();
}*/
while((ch=(char)is2.readByte()) != 0x00) {
System.out.print(ch+"");
}
}
System.out.println("\nTotal no of vehicles:"+totalVehicles);
System.out.println("Total no of Persons:"+totalPersons);
write_in_file(totalVehicles,totalPersons);
} catch (IOException i) {
System.out.println("error in write");
}
}
private void write_in_file(int totalVehicles, int totalPersons) {
try {
FileWriter fstream = new FileWriter("finalOutput.data");
BufferedWriter out = new BufferedWriter(fstream);
out.write("Number of vehicles involved"+"\t"+totalVehicles);
out.write("\nNumber of persons involved"+"\t"+totalPersons);
out.close();
} catch(Exception e) {
e.printStackTrace();
}
}
}
输出：
148308 1 4.774904982E-314结果
189429102 540161068 1.4275957977117199E-71结果
512 576 6.903600071305329E-93 8,98
37966848 512 1.7668797952966E-311结果
三月4,2006
37966848 256 2.8513257442947E-311结果
四月8,2011
38683904 512 2.3101107177838E-311军14,06
38683904 256 6.792508527386E-312四月22,2005
38683904 256 1.2216329768334E-311月1,04
38683904 768 2.3099515681247E-311七月9,83
38813952 256 6.802588006634E-312 4月1998年
38813952 512 6.802588006634E-312 2011年6月14日
38813952 512 1.7667206456376E-311 99年9月8日
39344128结果
车辆总号：576033218
人总号：540165485
148308 1 4.774904982E-314
189429102 540161068 1.4275957977117199E-71
512 576 6.903600071305329E-93 8,98 37966848 512 1.7668797952966E-311
Mar 4,2006 37966848 256 2.8513257442947E-311
Apr 8,2011 38683904 512 2.3101107177838E-311 Jun 14,06 38683904 256 6.792508527386E-312 Apr 22,2005 38683904 256 1.2216329768334E-311 Oct 1,04 38683904 768 2.3099515681247E-311 Jul 9,83 38813952 256 6.802588006634E-312 Aug 4. 1998 38813952 512 6.802588006634E-312 Jun 14, 2011 38813952 512 1.7667206456376E-311 Sep 8, 99 39344128
Total no of vehicles:576033218 Total no of Persons:540165485
请帮忙提前me..Thanks !!
Please help me..Thanks in advance!!
推荐答案
通过猜测是，你的数据存储为小端。 DataInputStream以是大端。 （如果你不知道什么是字节顺序看 http://en.wikipedia.org/wiki/Endianness）
By guess is that you data is store as little-endian. DataInputStream is big-endian. (If you are not sure what endianness is see http://en.wikipedia.org/wiki/Endianness)
做最简单的事情是把文件读入一个单一的直接的ByteBuffer ，它允许您设置的字节顺序。
The simplest thing to do is to read the file into a single direct ByteBuffer which allows you to set the byte order.
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