使用Javascript:创建一个持久绑定功能 [英] Javascript: Creating a persistently bound function
问题描述
我意识到这样一个问题是问pretty频繁(我大概看过过去几天试图了解如何解决这个问题他们每个人) - 但在这种情况下,当我相当有信心,我知道为什么发生这种情况,我挣扎实现一个实际的解决方案。
I realise a question like this is asked pretty frequently (I've probably read every one of them over the past few days trying to understand how to fix this) - but in this case, while I'm fairly confident I know why this is happening, I'm struggling to implement an actual solution.
我建立使用Node.js的,但有与创建与原型功能不会丧失时,他们正在通过周围的绑定的对象麻烦的小应用程序。
I'm building a small application using Node.js but having trouble with creating an object with prototype functions that won't lose their binding when they're passed around.
下面是我到目前为止有:
Here's what I have so far:
foo.js
var Foo = module.exports = function(server) {
this.server = server;
// some other stuff
};
Foo.prototype.send = function(data) {
server.doStuff(data);
};
Foo.prototype.sendData = function(data) {
// do stuff with data;
this.send(data);
};
bar.js
var Bar = module.exports = function() {
this.dataStore = // data store connection;
};
Bar.prototype.getSomething(data, callback) {
this.dataStore.get(data, function(err, response) {
callback(response);
});
};
main.js
var Foo = require('./foo');
var Bar = require('./bar');
var aFoo = new Foo(server);
var aBar = new Bar();
// at some point do:
aBar.getSomething(data, aFoo.sendData);
正如你可能想象,传递一个用作回调函数aFoo.sendData导致它失去其绑定到aFoo,所以无法找到富发送功能。
As you can probably imagine, passing that aFoo.sendData function for use as a callback causes it to lose its binding to aFoo, so it is unable to find the 'send' function on Foo.
我将如何修改美孚这样的SendData保持其绑定到富?有没有更好的方法来组织这个code,使这是没有必要的?
How would I modify Foo so that sendData maintains its binding to Foo? Is there a better way to structure this code so that this isn't necessary?
推荐答案
您简单封装在一个匿名函数调用aFoo.sendData:
You simple wrap the call to aFoo.sendData in an anonymous function:
aBar.getSomething(data, function () {
aFoo.sendData();
});
由于您参考 aFoo.sendData code>,提到
。当使用匿名函数,你不引用功能;你只是调用它作为对这个
在的SendData
不再<$ C $ C> aFoo aFoo
实例的方法,那么这个
还是 aFoo
。
Because your referencing aFoo.sendData
, the reference to this
inside sendData
is no longer aFoo
. When using the anonymous function, you're not referencing the function; you're simply invoking it as a method on the aFoo
instance, so this
is still aFoo
.
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