比特集,并从整数/长 [英] BitSet to and from integer/long
问题描述
如果我有,我想上执行位操作整数,我怎么可以加载它变成一个java.util.BitSet中?我怎样才能将其转换回int或长时间?我不那么在意BitSet的大小 - 它永远是长32或64位。我只是想使用set(),清(),nextSetBit()和nextClearBit()方法,而不是位运算符,但我无法找到一个简单的方法来初始化位以数字类型设置。
If I have an integer that I'd like to perform bit manipulation on, how can I load it into a java.util.BitSet? How can I convert it back to an int or long? I'm not so concerned about the size of the BitSet -- it will always be 32 or 64 bits long. I'd just like to use the set(), clear(), nextSetBit(), and nextClearBit() methods rather than bitwise operators, but I can't find an easy way to initialize a bit set with a numeric type.
推荐答案
以下code创建一个位从长期的价值和副反之亦然设置:
The following code creates a bit set from a long value and vice versa:
public class Bits {
public static BitSet convert(long value) {
BitSet bits = new BitSet();
int index = 0;
while (value != 0L) {
if (value % 2L != 0) {
bits.set(index);
}
++index;
value = value >>> 1;
}
return bits;
}
public static long convert(BitSet bits) {
long value = 0L;
for (int i = 0; i < bits.length(); ++i) {
value += bits.get(i) ? (1L << i) : 0L;
}
return value;
}
}
编辑:现在两个方向,@leftbrain:事业,你是对的。
EDITED: Now both directions, @leftbrain: of cause, you are right
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