遍历一个char位 [英] Iterating bits of a char

问题描述

假设我有字符C的ASCII code是 0110 0111 。我怎么可以遍历其位？我想建立从这些1的向量和0 ....

Assuming I have char "C" whose ascii code is 0110 0111. How can I iterate over its bits? I would like to build a vector from these 1's and 0's....

推荐答案

您可以轻松地在他们使用按位运算符迭代：

You can easily iterate over them using bitwise operators:

char c = 'C';
for (int i = 0; i < 8; ++i)
{
  // extract the i-th bit
  int b = ((c & 1<<i) >> i);
  // b will be 1 if i-th bit is set, 0 otherwise

  // do whatever you want with b
}

您可以优化它（如在评论建议）：

you can optimize it (as suggested in comments):

int b = ((c >> i) & 1);

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