帮助翻译反射解构到编译code [英] Help translating Reflector deconstruction into compilable code

问题描述

所以我反射-ING一些框架2.0 code和具有以下解构结束

So I am Reflector-ing some framework 2.0 code and end up with the following deconstruction

fixed (void* voidRef3 = ((void*) &_someMember))
{
...
}

这不会编译由于 fixed语句赋值的右侧可能不是一个施法前pression

据我所知，反射器只能近似，一般我可以看到一个清晰的路径，但是这是我经历过的外面了一下。

I understand that Reflector can only approximate and generally I can see a clear path but this is a bit outside my experience.

问：什么是反射器试图给我描述

Question: what is Reflector trying to describe to me?

更新：

我也看到以下

fixed (IntPtr* ptrRef3 = ((IntPtr*) &this._someMember))

更新：

所以，作为米奇说，它不是一个位操作符，而是一个AddressOf运算

So, as Mitch says, it is not a bitwise operator, but an addressOf operator.

问题现在是：

fixed (IntPtr* ptrRef3 = &_someMember)

失败，XXX *'到'System.IntPtr *的无法隐式转换类型'。一个显式转换存在（是否缺少强制转换？）'编译错误。

所以，我似乎如果我这样做，如果我不给该死该死。任何想法？

So I seemed to be damned if I do and damned if I dont. Any ideas?

更新：

我想我已经想通。一次偶然的机会我又回到了使用无效* 除权pression并取消了管型和VS停止抱怨，因为我从参加该谈话聚集了无效* 和 IntPtr的* 是等价的，我只是换出来，造成这样的：

I think i have it figured. By chance I went back to the expression that was using void* and removed the casts and VS stopped complaining and since I gathered from the participants in this conversation that void* and intptr* are equivalent I simply swapped them out, resulting in this:

fixed (void* ptrRef3 = &_someMember)

和VS停止抱怨。有人可以验证

and VS stopped complaining. Can someone verify that

fixed (void* ptrRef3 = &_someMember)

等同于

fixed (IntPtr* ptrRef3 = &_someMember)

推荐答案

据正在 _someMember 的地址，并将其转换为（无效* ）（即指针地址），然后设置到该地址的位置。

It is taking the address of _someMember and casting it to (void *) (i.e. a pointer address), and then setting a location to that address.

的固定语句'销'的对象，$ P $来自移动它pvents的GC。

The fixed statement 'pins' the object, and prevents the GC from moving it around.

在'＆放大器;'在这方面采用的是地址中'操作，不按位与。

The '&' used in that context is the 'Address Of' operator, not Bitwise And.

在回应更新的问题：

你试过：

fixed (void* voidRef3 = &_someMember) 
{ 
... 
}

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