在黑莓应用程序弹出多个屏幕 [英] Popping multiple screens in a BlackBerry application

问题描述

我写一个黑莓应用程序，它有一个用户浏览（如调查）多个屏幕。提交调查后，应用程序必须返回到开始屏幕，在这之后，他们绝不允许导航回到这是previously显示屏幕。

什么是实现这一正确的方法是什么？

目前我打电话

<$p$p><$c$c>UiApplication.getUiApplication().popScreen(UiApplication.getUiApplication().getActiveScreen());

多次有不同的屏幕。有没有可能是一个更好的解决方案，以返回到开始屏幕？

解决方案

UiApplication.getScreenCount（）总会给你屏幕的数量，所以你可以这样做（从的随时随地的，它甚至没有被任何特定屏幕类）：

公共无效popToRoot（）{
      UIApplication的应用= UiApplication.getUiApplication（）;
      而（app.getScreenCount（）→1）{
         app.popScreen（app.getActiveScreen（））;
      }
   }


I writing a BlackBerry app which has multiple screens that the user navigates through (like a survey). After submitting the survey the app must return to the start screen, after which, they must not be allowed to navigate back to the screens which were previously shown.

What would be the correct way to implement this?

Currently I'm calling

UiApplication.getUiApplication().popScreen(UiApplication.getUiApplication().getActiveScreen());

as many times as there were different screens. Is there perhaps a more elegant solution to get back to the start screen?

解决方案

UiApplication.getScreenCount() will always give you the number of screens, so you can just do this (from anywhere, it doesn't even have to be from any particular Screen class):

   public void popToRoot() {
      UiApplication app = UiApplication.getUiApplication();
      while (app.getScreenCount() > 1) {
         app.popScreen(app.getActiveScreen());
      }
   }

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