Java的突破和回访 [英] Java breaking vs returning

问题描述

我使用的返回true一个布尔值。当这样的事情发生了：

I am using a boolean that returns true. When something like this happens:

public boolean t(String label, String[] arguments) {
    boolean j = false;
    if (!j) {
        return true;
    }
    return true;
}

不过，这个布尔里面我有一个开关语句。正如你可能知道，你打破了通常开关语句。不过我做这样的事情测试布尔值是真还是假。我将返回一个switch语句内，或打破，如果一个布尔是假的？

However, inside of this boolean I have a switch statement. As you may know, you break out of switch statements usually. However I am doing something like this testing for booleans to be true or false. Would I return inside of a switch statement, or break if a boolean is false?

一个例子是这样的：

switch (arguments.length) {
    case 0:
        if (j) return true;
        break;
    default:
        break;
}

这将是更为有用，交换回如此休息，或保持不变？

Which would be more useful, exchanging return true for break, or keep it the same?

推荐答案

A 破语句将终止开关的执行语句，并继续在法。 A 收益语句将离开完全的方法。

A break statement would terminate execution of the switch statement and continue in the method. A return statement would leave the method entirely.

这是preference的事，真的，至于哪一个更好。归结到一点，方法设计。

It's a matter of preference, really, as to which one is better. It comes down to method design.

我会在大多数情况下，说喜欢你有以上，倒不如直接使用收益语句，并完全退出的方法。

I would say in most cases like you have above, it would be better to directly use a return statement and leave the method entirely.

这是说，这样的：

public boolean t(String label, String[] arguments) {
    boolean j = false;
    if (!j) {
        return true;
    }
    return true;
}

可以简化为这样：

Can be simplified to this:

public boolean t(String label, String[] arguments) {   
    return true;
}

如果你只是从一个变量检查​​一个条件，那么你并不需要一个开关语句;它不是最优的。

我做这样的测试东西布尔值是true或false

I am doing something like this testing for booleans to be true or false

您应该不是真正的测试布尔变量是真或假，只是返回它们。

You shouldn't really "test" for boolean variables to be true or false, just return them.

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