有没有在C＃中XNOR（逻辑双条件）运算符？ [英] Is there XNOR (Logical biconditional) operator in C#?

问题描述

我是新的C＃和找不到 XNOR 运营商提供该真值表：

I'm new to C# and could not find XNOR operator to provide this truth table:

a  b    a XNOR b
----------------
T  T       T
T  F       F
F  T       F
F  F       T

有没有这个特定的运算？或者，我需要用！（A ^ B）？

Is there a specific operator for this? Or I need to use !(A^B)?

推荐答案

同或仅仅是针对布尔平等;使用 A ==乙。

XNOR is simply equality on booleans; use A == B.

这是错过一件容易的事情，因为平等是不是普遍适用于布尔值。而且有语言的地方不一定会工作。例如，在C，任何非零标值视为真，所以两个真的值可以是相等的。但问题是标签 C＃，其中有应我们说，乖巧的布尔值。

This is an easy thing to miss, since equality isn't commonly applied to booleans. And there are languages where it won't necessarily work. For example, in C, any non-zero scalar value is treated as true, so two "true" values can be unequal. But the question was tagged c#, which has, shall we say, well-behaved booleans.

另请注意，这并不能概括位操作，您希望 0×1234 XNOR 0x5678的== 0xFFFFBBB3 （假设32位）。对于这一点，你需要从其他业务建立起来，像〜（A ^ B）。 （注：！〜，而不是 ）

Note also that this doesn't generalize to bitwise operations, where you want 0x1234 XNOR 0x5678 == 0xFFFFBBB3 (assuming 32 bits). For that, you need to build up from other operations, like ~(A^B). (Note: ~, not !.)

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