与整数布尔运算 [英] boolean operations with integers

问题描述

这大概是pretty基本...但我似乎并没有得到它：

This is probably pretty basic... but I don't seem to get it:

如何

(2 & 1) = 0
(3 & 1) = 1
(4 & 1) = 0

等

以上这个模式似乎帮助寻找偶数

This pattern above seems to help find even numbers

或

(0 | 1) = 1
(1 | 1) = 1
(2 | 1) = 3
(3 | 1) = 4
(4 | 1) = 5
(5 | 1) = 5

我知道如何布尔代数位之间的作品。但我不明白怎么代数与布尔整数（在至少在C＃）的作品。

I know how boolean algebra works between bits. But I don't understand how Boolean algebra works with integers (in C# at the least).

先谢谢了。

推荐答案

它工作在C＃中以同样的方式，因为它在二进制一样。

It works the same way in C# as it does in binary.

2 | 1 = 3 和 4 | 1 = 5 。

要理解这一点，你需要考虑的1,2,3,4二进制重新presentation和5：

To understand this, you need to think about the binary representation of 1,2,3,4,and 5:

010 | 001 = 011 和 100 | 001 = 101 。

同样的：

010安培; 001 = 000 和 011安培; 001 = 001

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