犰狳C ++的线性代数库：如何创建布尔矢量 [英] Armadillo C++ linear algebra library : How to create vector of boolean

问题描述

最近，我开始使用犰狳C ++库。鉴于我的C ++编码技能不是很大，我发现这对线性代数很友好。我也使用了与我一起MATLAB加快工作速度为许多重建算法。

Recently I started using Armadillo C++ library. Given my C++ coding skills are not that great, I found this very friendly for linear algebra. I am also using that along with my matlab to speed things up for many of reconstruction algorithm.

我确实需要创建布尔的一个载体，我会使用这个库，而不是preFER。然而，我无法弄清楚如何做到这一点。我试着用uvec;但是，文件似乎表明它不能与布尔使用。

I do need to create a vector of boolean and I would prefer using this library rather than . However, I could not figure out how to do it. I tried using uvec; but, documentation seems to indicate that it can not be used with boolean.

任何帮助将是AP preciated。

Any help would be appreciated.

问候，
Dushyant

Regards, Dushyant

推荐答案

考虑使用矩阵垫＆LT; unsigned char型＆GT; ，它通常会消耗内存相同数量的矩阵布尔值。

Consider using a matrix Mat<unsigned char>, it will normally consume the same amount of memory as a matrix of boolean values.

借助犰狳文档指出，一个矩阵垫＆LT;＆型GT ; ，可以是以下类型：浮动，双击，的std ::复杂＆LT;浮动＆GT; ，的std ::复杂＆LT;双＆GT; ，字符，短， INT ，长和上面的签名版本。所以，你是对的，没有类型的矩阵布尔。

The Armadillo documentation states that a matrix Mat<type>, can be of the following types: float, double, std::complex<float>, std::complex<double>, char, short, int, long and unsigned versions of the above. So you are right there is no matrix of type bool.

您将无法通过创建较 unsigned char型数值矩阵布尔值矩阵保存任何记忆（一布尔消耗型8位）。这是因为，在C ++中的每个数据类型必须寻址;它必须至少1个字节长的，以便它可以创建一个指针指向它

You will not save any memory by creating a matrix of bool values compared to a matrix of unsigned char values (a bool type consumes 8 bits). This is because in C++ every data type must be addressable; it must be at least 1 byte long so that it is possible to create a pointer pointing to it.

这篇关于犰狳C ++的线性代数库：如何创建布尔矢量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！