简化布尔防爆pression（A'BC）+（A'B'C）+（A'BC）+（AB'C） [英] Simplifying Boolean Expression (A'BC) + (A'B'C) + (A'BC) + (AB'C)

问题描述

请帮我简化了这一个。我有点新的这些..

please help me with simplifying this one. I am a bit new to these..

(A'BC') + (A'B'C) + (A'BC) + (AB'C)

这本书我用表演和答案，这一点，

the book i use shows and answer, which is,

Answer = A'B + B'C

我试过了简化，但我得到stucked两个eXors，
我简化到目前为止是这样的...

I tried simplifying, but I get stucked with two eXors,
my simplification so far goes like this...

(A'BC') + (A'B'C) + (A'BC) + (AB'C)
A (BC' + B'C) + C (A'B + AB')

这似乎并没有被写入的方式，请人帮我简化，
并请一步一步展现，因为我是那种新..

此外，我不明白如何进一步简化EXOR ..

This doesn't seem to be a write way, Please someone help me simplify this,
and please show step by step, as I am sort of new..
Also I don't get how to simplify eXor further..

推荐答案

您有规则 X'+ X = TRUE 。 SO

(A'BC') + (A'B'C) + (A'BC)  + (AB'C) = 
(A'BC') + (A'BC)  + (A'B'C) + (AB'C) =   // just permuting the terms
A'B(C' + C)       + (A' + A)B'C      =   // factoring
A'B               + B'C

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