使用布尔前pression的方法 [英] A method using Boolean expression

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本文介绍了使用布尔前pression的方法的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

用户必须挑选2号1)加入2)减3)乘4)除以5)退出。
2号的用户条目可以是0-9,小数点,或者减号,和其他任何一个er​​ror.I需要创建一个方法来检查用户输入,通过使用真或假的布尔前pression。我该怎么把在布尔前pression

  Console.Write(输入号码1:NUM1);
NUM1 = Convert.ToDouble(到Console.ReadLine());Console.Write(输入号码2,NUM2);
NUM2 = Convert.ToDouble(到Console.ReadLine());如果属实)
{}开关(输入)
{
    情况1:
        Console.WriteLine(\\ tResults:{0},添加(NUM1,NUM2));
        打破;
    案例2:
        Console.WriteLine(\\ tResults:{0},减(NUM1,NUM2));
        打破;
    案例3:
        Console.WriteLine(\\ tResults:{0},乘(NUM1,NUM2));
        打破;
    情况4:
        Console.WriteLine(\\ tResults:{0},除(NUM1,NUM2));
        打破;
    默认:        //Console.WriteLine(\"Invalid菜单选择\\ t重试);
        //Console.ReadLine();
        返回;
}Console.WriteLine(preSS任意键...);
Console.ReadKey();
Console.Clear();


解决方案

检查输入的只有数字:

 正则表达式R =新的正则表达式(@^ [ - ] [。] [\\ D] {1,} {0,1} [\\ D] {0,} $);
如果(r.IsMatch(NUM1)及&放大器; r.IsMatch(NUM2)及&放大器; num1.Count(J = GT;Ĵ==)下'。'; 2和;&放大器; num2.Count(J = >Ĵ==)LT'。'; 2)
{
//做一点事
}

如果两个数字仅NUMS,然后用你的switch语句。

如果输入包含字母,然后显示一些信息给用户讲,只有编号

The user has to pick 2 number to 1) Add 2) Subtract 3) Multiply 4) Divide 5) Quit. The 2 number that the user entry can be 0-9, a decimal point, or minus sign, and anything else is a error.I need to create a method to check the user entry , by using a true or false Boolean expression. what do I put in the Boolean expression

Console.Write("Enter Number 1: ", num1);
num1 = Convert.ToDouble(Console.ReadLine());

Console.Write("Enter Number 2: ", num2);
num2 = Convert.ToDouble(Console.ReadLine());

if (true)
{

}

switch (input)
{
    case 1:
        Console.WriteLine("\tResults: {0}", Add(num1, num2));
        break;
    case 2:
        Console.WriteLine("\tResults: {0}", Subtract(num1, num2));
        break;
    case 3:
        Console.WriteLine("\tResults: {0}", Multiply(num1, num2));
        break;
    case 4:
        Console.WriteLine("\tResults: {0}", Divide(num1, num2));
        break;
    default:

        //Console.WriteLine("Invalid Menu Selection.\t Try Again");
        //Console.ReadLine();
        return;
}

Console.WriteLine("Press any key...");
Console.ReadKey();
Console.Clear();

解决方案

Check that the input is only numbers:

Regex r = new Regex(@"^[-.]?[\d]{1,}[.]{0,1}[\d]{0,}$");
if(r.IsMatch(num1) && r.IsMatch(num2) && num1.Count(j => j == '.') < 2 && num2.Count(j => j == '.') < 2)
{
//Do something
} 

And if both numbers are only nums, then use your switch statement.

If the input contains letters, then show some message to the user telling that only numbers are available

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