如何使用RestSharp访问HTTP请求的身体？ [英] How to access the HTTP request body using RestSharp?
问题描述
我要建一个RESTful API客户端在C＃.NET 3.5。
I'm building a RESTful API client in C# .NET 3.5.
我第一次开始与构建它的好老 HttpWebClient （和 HttpWebResponse ），我可以做任何我想要的用。我很高兴。我被困在唯一的事是从JSON响应自动反序列化。
I first started building it with the good old HttpWebClient (and HttpWebResponse), I could do whatever I wanted with. I were happy. The only thing I was stuck on was the automatic deserialization from JSON response.
所以，我听说过一个美妙的库称为RestSharp（104.1），从而简化了REST的API客户端的发展，并自动反序列化JSON和XML响应。我打开这一切我的code，但现在我知道，我不能做的事情我可以做 HttpWebClient 和 HttpWebResponse ，如访问和编辑的原始请求主体。
So, I've heard about a wonderful library called RestSharp (104.1) which eases the development of RESTful API clients, and automatically deserialize JSON and XML responses. I switched all my code on it, but now I realize I can't do things I could do with HttpWebClient and HttpWebResponse, like access and edit the raw request body.
任何人有一个解决方案？
Anyone has a solution ?
编辑：我知道如何设置请求主体（以 request.AddBody（）），我的问题是，我想这个请求体中的字符串，编辑它，并重新设置请求（更新请求体上飞）
Edit : I know how to set the request body (with request.AddBody()), my problem is that I want to get this request body string , edit it, and re-set it in the request (updating the request body on the fly)
推荐答案
请求的身体是一种类型的参数。要添加一个，你可以做其中的一个......
The request body is a type of parameter. To add one, you can do one of these...
req.AddBody(body);
req.AddBody(body, xmlNamespace);
req.AddParameter("text/xml", body, ParameterType.RequestBody);
req.AddParameter("application/json", body, ParameterType.RequestBody);
要取回身体参数，你可以看看在 req.Parameters 藏品，其中键入等于以 ParameterType.RequestBody 。
To retrieve the body parameter you can look for items in the req.Parameters collection where the Type is equal to ParameterType.RequestBody.
请参阅code为 RestRequest 类的<a href =https://github.com/restsharp/RestSharp/blob/master/RestSharp/RestRequest。 CS>这里。
See code for the RestRequest class here.
下面是关于 ParameterType.RequestBody RestSharp文档C> 不得不说：
Here is what the RestSharp docs on ParameterType.RequestBody has to say:
如果该参数设置，它的值将作为的身体 请求。参数的名称被忽略，所以是附加 RequestBody参数 - 只有1个被接受
If this parameter is set, it’s value will be sent as the body of the request. The name of the Parameter is ignored, and so are additional RequestBody Parameters – only 1 is accepted.
RequestBody只能在POST或PUT请求，因为他们实际上只 送一具尸体。
RequestBody only works on POST or PUT Requests, as only they actually send a body.
如果您有GetOrPost参数，以及，他们将覆盖 RequestBody - RestSharp不会将它们结合起来，但是这反而 扔RequestBody参数了。
If you have GetOrPost parameters as well, they will overwrite the RequestBody – RestSharp will not combine them but it will instead throw the RequestBody parameter away.
有关读取/上即时更新的身体参数，你可以试试：
For reading/updating the body parameter on-the-fly, you can try:
var body = req.Parameters.Where(p => p.Type == ParameterType.RequestBody).FirstOrDefault();
if (body != null)
{
Console.WriteLine("CurrentBody={0}", body.Value);
body.Value = "NewBodyValue";
}
要是做不到这一点，创建 RestRequest 对象的新副本，不同的身体。
Or failing that, create a new copy of the RestRequest object with a different body.
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