在Android的短信座 [英] Block SMS in android
问题描述
我开发，我想阻止某些特定numbers.For测试我做短信从这个数字，我在if条件的短信应用，但这code未阻止该号码的短信。我尝试最好的，但我以前不解决。任何一个帮助me.Here是我的code结果
Sms.java
公共类短信扩展广播接收器{
最后SmsManager短信= SmsManager.getDefault（）; @覆盖
公共无效的onReceive（上下文的背景下，意图意图）{ //获取地图从意图扩展数据。
最后的捆绑包= intent.getExtras（）; 尝试{ 如果（捆绑！= NULL）{ 最终目标[] = pdusObj（对象[]）bundle.get（的PDU）; 的for（int i = 0; I＆LT; pdusObj.length;我++）{ SmsMessage currentMessage = SmsMessage
（（字节[]）pdusObj [I]）.createFromPdu;
字符串phoneNumber的= currentMessage
.getDisplayOriginatingAddress（）; 字符串senderNum = phoneNumber的;
字符串消息= currentMessage.getDisplayMessageBody（）; Log.i（SmsReceiver，senderNum：+ senderNum
+的消息：+消息）;
//显示警报
INT持续时间= Toast.LENGTH_SHORT;
吐司面包= Toast.makeText（背景下，senderNum：
+ senderNum +，留言：+消息，持续时间）;
toast.show（）;
如果（senderNum ==+ 923215619915）{
Toast.makeText（背景下，你如果条件R IN，Toast.LENGTH_LONG）.show（）;
abortBroadcast（）;
} } //结束for循环
} //包是空 }赶上（例外五）{
Log.e（SmsReceiver，异常smsReceiver+ E）; }
}
}
的Manifest.xml
＆LT;？XML版本=1.0编码=UTF-8＆GT？;
＆LT;清单的xmlns：机器人=http://schemas.android.com/apk/res/android
包=com.example.tesingworkspace
安卓版code =1
机器人：=的versionName1.0＆GT; ＆LT;采用-SDK安卓的minSdkVersion =7
机器人：targetSdkVersion =19
/＆GT;
＆LT;使用许可权的android：NAME =android.permission.SEND_SMS＆GT;
＆LT; /使用许可权＆GT;
＆LT;使用许可权的android：NAME =android.permission.READ_CONTACTS/＆GT;
＆LT;使用许可权的android：NAME =android.permission.RECEIVE_SMS＆GT;
＆LT; /使用许可权＆GT;
＆LT;使用许可权的android：NAME =android.permission.READ_SMS/＆GT; ＆lt;应用
机器人：allowBackup =真
机器人：图标=@绘制/ ic_launcher
机器人：标签=@字符串/ APP_NAME
机器人：主题=@风格/ AppTheme＆GT;
＆LT;活动
机器人：名字=com.example.tesingworkspace.BroadCastSms
机器人：标签=@字符串/ APP_NAME＆GT;
＆所述;意图滤光器＆gt;
＆lt;作用机器人：名字=android.intent.action.MAIN/＆GT; ＆LT;类机器人：名字=android.intent.category.LAUNCHER/＆GT;
＆所述; /意图滤光器＆gt;
＆LT; /活性GT; ＆lt;接收机器人：名字=com.example.tesingworkspace.Sms＆GT;
＆所述;意图滤光器＆gt;
＆lt;作用机器人：名字=android.provider.Telephony.SMS_RECEIVED/＆GT;
＆所述; /意图滤光器＆gt;
＆LT; /接收器＆GT; ＆LT; /用途＆gt; ＆LT; /清单＆GT;
您需要做的是调试code的最好的事情，你有难$ C $光盘格式的电话号码可能会或可能不会发生，确保在出现什么格式接收机的电话号码？当我工作了它我会发送消息通过 0333xxx-XXXX 号码和我收到的 + 92xxx 。但它不能确定所有的，不同的电信公司可能会使用不同的格式，你应该使用
如果（number.equals（+ 92333xxx-XXXXX））或更好的使用包含，即实际上使其更适合匹配号码，并移除格式错误的可能性
如果（number.contains（333xxx-XXXXX））{
//你的code中止的消息
}
希望这有助于
i developing an application where i want to block SMS of some specific numbers.For testing i do SMS from that number that i have in IF CONDITION but this code is not blocking that number SMS. i try best but did't resolved. any one help me.Here is my code
Sms.java
public class Sms extends BroadcastReceiver {
final SmsManager sms = SmsManager.getDefault();
@Override
public void onReceive(Context context, Intent intent) {
// Retrieves a map of extended data from the intent.
final Bundle bundle = intent.getExtras();
try {
if (bundle != null) {
final Object[] pdusObj = (Object[]) bundle.get("pdus");
for (int i = 0; i < pdusObj.length; i++) {
SmsMessage currentMessage = SmsMessage
.createFromPdu((byte[]) pdusObj[i]);
String phoneNumber = currentMessage
.getDisplayOriginatingAddress();
String senderNum = phoneNumber;
String message = currentMessage.getDisplayMessageBody();
Log.i("SmsReceiver", "senderNum: " + senderNum
+ "; message: " + message);
// Show Alert
int duration = Toast.LENGTH_SHORT;
Toast toast = Toast.makeText(context, "senderNum: "
+ senderNum + ", message: " + message, duration);
toast.show();
if(senderNum=="+923215619915"){
Toast.makeText(context, "You r in if condition", Toast.LENGTH_LONG).show();
abortBroadcast();
}
} // end for loop
} // bundle is null
} catch (Exception e) {
Log.e("SmsReceiver", "Exception smsReceiver" + e);
}
}
}
Manifest.xml
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.tesingworkspace"
android:versionCode="1"
android:versionName="1.0" >
<uses-sdk android:minSdkVersion="7"
android:targetSdkVersion="19"
/>
<uses-permission android:name="android.permission.SEND_SMS" >
</uses-permission>
<uses-permission android:name="android.permission.READ_CONTACTS" />
<uses-permission android:name="android.permission.RECEIVE_SMS" >
</uses-permission>
<uses-permission android:name="android.permission.READ_SMS"/>
<application
android:allowBackup="true"
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" >
<activity
android:name="com.example.tesingworkspace.BroadCastSms"
android:label="@string/app_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver android:name="com.example.tesingworkspace.Sms">
<intent-filter>
<action android:name="android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
</application>
</manifest>
The best thing you need to do is debug your code, you have hard coded the phone number in a format that may or may not occur, make sure in what format your receiver phone number appears? When I was working over it I was sending message over 0333xxx-xxxx number and I was receiving as +92xxx. But it's not sure for all, different telecommunication companies may use different format, for that you should use
if(number.equals("+92333xxx-xxxxx")) or better use a contains, that would actually make it more appropriate to match the number and remove the possibility of format error
if(number.contains("333xxx-xxxxx")){
// Your code to abort message
}
Hope this helps
这篇关于在Android的短信座的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
