打开浏览器与Java按钮链接？ [英] Open a link in browser with java button?

问题描述

我怎样可以打开一个按钮，点击默认浏览器的链接，沿行

How can I open a link in default browser with a button click, along the lines of

button.addActionListener(new ActionListener() {
    public void actionPerformed(ActionEvent e) {
        open("www.google.com"); // just what is the 'open' method?
    }
});

推荐答案

使用的<一个href=\"http://docs.oracle.com/javase/7/docs/api/java/awt/Desktop.html#browse%28java.net.URI%29\">Desktop#browse(URI)方法。它会打开一个URI在用户的默认浏览器。

Use the Desktop#browse(URI) method. It opens a URI in the user's default browser.

public static void openWebpage(URI uri) {
    Desktop desktop = Desktop.isDesktopSupported() ? Desktop.getDesktop() : null;
    if (desktop != null && desktop.isSupported(Desktop.Action.BROWSE)) {
        try {
            desktop.browse(uri);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

public static void openWebpage(URL url) {
    try {
        openWebpage(url.toURI());
    } catch (URISyntaxException e) {
        e.printStackTrace();
    }
}

这篇关于打开浏览器与Java按钮链接？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！