发送提交按钮的值时，得到的形式发布 [英] Send value of submit button when form gets posted
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问题描述
我有名称的列表，并与产品名一些按钮。当其中一个按钮被点击发送到一个PHP脚本列表的信息，但我不能点击提交按钮发送它的价值。它是如何做？
我煮了我的code到以下内容：
I have a list of names and some buttons with product names. When one of the buttons is clicked the information of the list is sent to a PHP script, but I can't hit the submit button to send its value. How is it done? I boiled my code down to the following:
发送页面：
<html>
<form action="buy.php" method="post">
<select name="name">
<option>John</option>
<option>Henry</option>
<select>
<input id='submit' type='submit' name = 'Tea' value = 'Tea'>
<input id='submit' type='submit' name = 'Coffee' value = 'Coffee'>
</form>
</html>
接收页：buy.php
<?php
$name = $_POST['name'];
$purchase = $_POST['submit'];
//here some database magic happens
?>
除了发送提交按钮价值的作品完美的一切。
Everything except sending the submit button value works flawlessly.
推荐答案
按钮名称不提交的，所以PHP $ _ POST ['提交'] 值不组。正如使用isset（$ _ POST ['提交']）计算结果为假。
The button names are not submit, so the php $_POST['submit'] value is not set. As in isset($_POST['submit']) evaluates to false.
<html>
<form action="" method="post">
<input type="hidden" name="action" value="submit" />
<select name="name">
<option>John</option>
<option>Henry</option>
<select>
<!--
make sure all html elements that have an ID are unique and name the buttons submit
-->
<input id="tea-submit" type="submit" name="submit" value="Tea">
<input id="coffee-submit" type="submit" name="submit" value="Coffee">
</form>
</html>
<?php
if (isset($_POST['action'])) {
echo '<br />The ' . $_POST['submit'] . ' submit button was pressed<br />';
}
?>
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