如何选择一个目录，并使用Python中Tkinter的存储位置 [英] How to select a directory and store the location using tkinter in Python

问题描述

我创建一个浏览按钮，我只希望返回路径的GUI。我一直在寻找使用code像下面的解决方案。

I am creating a GUI with a browse button which I only want to return the path. I've been looking at solutions using code like below.

Tkinter.Button(subframe, text = "Browse", command = self.loadtemplate, width = 10).pack()

   def loadtemplate(self): 
        filename = tkFileDialog.askopenfilename(filetypes = (("Template files", "*.tplate")
                                                             ,("HTML files", "*.html;*.htm")
                                                             ,("All files", "*.*") ))
        if filename: 
            try: 
                self.settings["template"].set(filename)
            except: 
                tkMessageBox.showerror("Open Source File", "Failed to read file \n'%s'"%filename)

不过，我知道Tkinter的有一个内置的 askopenfilename 这是打开文件code的一个超级简单的一条线。是否有某种方式来修改这个返回目录而不是一个文件？难道还有比code我张贴？

However I know Tkinter has a built in askopenfilename which is a super easy one line of code for opening files. Is there some way to modify this to return the directory instead of a file? Is there a smaller option than the larger chunk of code I posted?

推荐答案

看来， tkFileDialog.askdirectory 应该工作。 文档

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