如何创建QT正确的退出按钮 [英] How to create a correct exit button in qt

问题描述

我试图创建一个退出按钮正确关闭我在QT作出的GUI。我曾尝试以下列方式这样做：

I'm trying to create an exit button that correctly closes the GUI I have made in QT. I have tried doing this in the following way:

#include <QtGui/QApplication>
#include "mainwindow.h"

int main(int argc, char *argv[])
{
QApplication a(argc, argv);

int window_width = QApplication::desktop()->width();
int window_height = QApplication::desktop()->height();

MainWindow w;

QPushButton * quit_btn = new QPushButton;
quit_btn->setParent(w.centralWidget());
quit_btn->setGeometry(window_width-50,12,32,32);

QObject::connect(quit_btn,SIGNAL(clicked()),qApp,SLOT(quit()));

w.resize(window_width,window_height);
w.show();

return a.exec();
}

不幸的是，当我按下按钮，调试器提供了一个错误：

Unfortunately when I push the button, the debugger gives an error:

Invalid address specified to RtlFreeHeap( 003E0000, 0028F950 )

任何人都可以点我在正确的方向？

Can anybody point me in the right direction?

推荐答案

按钮的点击（）信号连接到你的主窗口的的close（） 插槽。事情的方式被正确地清理。

Connect the button's clicked() signal to your main window's close() slot. That way things are cleaned up properly.

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