如何更改使用JavaScript的一个按钮的背景图像? [英] How to change the background image of a button using JavaScript?
问题描述
我要改变使用Javascript按钮的背景图像。以下是我目前努力,但它失败。
I want to change the background image of a button using Javascript. Here is what I am currently trying, but it is failing.
HTML code -
HTML code -
<tr id="Rank1">
<td><button class="darkSquare"></button></td>
<td><button class="lightSquare" ></button></td>
<td><button class="darkSquare" ></button></td>
<td><button class="lightSquare" ></button></td>
<td><button id="e1" class="darkSquare" ></button></td>
<td><button class="lightSquare" ></button></td>
<td><button class="darkSquare" ></button></td>
<td><button class="lightSquare"> </button></td>
</tr>
JavaScript的code
JavaScript Code
initializer();
function initializer()
{
var tableRow = document.getElementById("Rank1");
var buttons = tableRow.getElementsByTagName("button");
for(b in buttons)
{
console.log(b.toString());
b.style.backgroundImage = "url('darkSquare.jpg')";
}
}
在控制台中,我得到一个错误说b.style是不确定的。
In the console, I get an error saying b.style is undefined.
推荐答案
为(... ...中)
循环不工作在JavaScript中这样,它应该是:
for (... in ...)
loops do not work that way in JavaScript it should be:
for (var b = 0; b < buttons.length; b++) {
buttons[b].style.backgroundImage = "url('darkSquare.jpg')";
}
为(... ...中)
某对象的所有的成员实际上迭代
for (... in ...)
actually iterates over all the "members" of an object
如。使用 VAR X = {A:1,B 2,C:3}
在的(在X VAR米)的console.log(M)
将产生
> a
> b
> c
这样的处理数组的作品,因为它认为指数的成员如下:
it kind of works with arrays because it considers the indices members like this:
var x = [1,2,3];
for (var m in x) console.log(m);
> 0
> 1
> 2
,因为它是给你的指标,如果他们的成员将无法区分。该缺陷是:
since it is giving you the indices as if they were members you can't distinguish. the pitfall is:
var x = [1,2,3];
x.stuff = 'boo!';
for (var m in x) console.log(m);
> 0
> 1
> 2
> stuff
一般的经验法则:只使用为(... ...中)在对象遍历成员时,
,使用为(VAR I = 0; I&LT; array.length,我++)
使用数组时
General Rule of Thumb: only use for (... in ...)
when iterating over members in an object, use for (var i = 0; i < array.length; i++)
when using arrays
的你总是可以欺骗和使用的:
for (var i = 0, item = x[i]; i < x.length; item=x[++i]) {
// now item is the current item
}
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