如何fopen（）函数在iPhone？ [英] How to fopen() on the iPhone?

问题描述

在iPhone SDK文档要求fopen（）函数是文件访问支持的方法，但我不能让它返回的文件句柄。我访问包含在我的项目目录。我已经试过的fopen文件名，目录/文件名，./文件名，./目录/文件名，/目录/文件名全部用一个空指针返回。有些人使用它，没有问题的报告，所以我敢肯定这是简单的东西！

The iPhone SDK docs claim fopen() is a supported method of file access but I am unable to get it to return a FILE handle. I am accessing a directory which is included in my project. I have tried fopen "filename","dir/filename","./filename","./dir/filename","/dir/filename" all returning with a null pointer. Some people report using it with no issue so I am sure it is something simple!

推荐答案

如果你想你的应用程序包中访问一个文件，你需要得到完整路径： [一个NSBundle mainBundle] pathForResource：FILENAME ofType：FILEEXTENSION]

if you're trying to access a file within your application bundle, you need to get the full path to it: [[NSBundle mainBundle] pathForResource: FILENAME ofType: FILEEXTENSION]

这将返回一个NSString，你可以拉出来UTF8字符串和传递给fopen。

This returns an NSString, which you can pull a UTF8String out of and pass to fopen.

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