蟒蛇ctypes的和的sysctl [英] python ctypes and sysctl

问题描述

我有以下code

import sys
from ctypes import *
from ctypes.util import find_library

libc = cdll.LoadLibrary(find_library("c"))
CTL_KERN = 1
KERN_SHMMAX = 34
sysctl_names = {
    'memory_shared_buffers' : (CTL_KERN, KERN_SHMMAX),
    }

def posix_sysctl_long(name):
    _mem = c_uint64(0)
    _arr = c_int * 2
    _name = _arr()
    _name[0] = c_int(sysctl_names[name][0])
    _name[1] = c_int(sysctl_names[name][1])
    result = libc.sysctl(_name, byref(_mem), c_size_t(sizeof(_mem)), None, c_size_t(0))
    if result != 0:
        raise Exception('sysctl returned with error %s' % result)
    return _mem.value

print posix_sysctl_long('memory_shared_buffers')

产生以下结果：

Traceback (most recent call last):
  File "test.py", line 23, in <module>
    print posix_sysctl_long('memory_shared_buffers')
  File "test.py", line 20, in posix_sysctl_long
    raise Exception('sysctl returned with error %s' % result)
Exception: sysctl returned with error -1

我客串我做错了什么。什么是正确的调用约定？我将如何找出究竟哪里出了问题？

I gues I did something wrong. What would be the correct calling convention? How would I find out what exactly went wrong?

推荐答案

您没有提供正确的值的sysctl功能。上）的sysctl（的参数的详细信息可以在这里找到 。

You are not providing the correct values to the sysctl function. Detailed information on the arguments of sysctl() can be found here.

下面是你的错误：

• 您已经忘记了的 nlen 的参数（第二个参数）


• 的 oldlenp 的参数是一个指针的大小，没有直接的大小

• You have forgotten the nlen argument (second argument)
• The oldlenp argument is a pointer to the size, not directly the size

下面是正确的函数（轻微改善）：

Here is the correct function (with minor improvement):

def posix_sysctl_long(name):
    _mem = c_uint64(0)
    _def = sysctl_names[name]
    _arr = c_int * len(_def)
    _name = _arr()
    for i, v in enumerate(_def):
        _name[i] = c_int(v)
    _sz = c_size_t(sizeof(_mem))
    result = libc.sysctl(_name, len(_def), byref(_mem), byref(_sz), None, c_size_t(0))
    if result != 0:
        raise Exception('sysctl returned with error %s' % result)
    return _mem.value

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