Java 2D的碰撞？ [英] Java 2D Collision?

问题描述

嘿家伙我正在做的2D Java小游戏，我试图找出如何使一个良好的碰撞code。我目前正在使用下面的code：

Hey guys i'm making a 2D java game and i'm trying to figure out how to make a good collision code. I am currently using the following code:

    public void checkCollision() {
    Rectangle player_rectangle = new Rectangle(player.getX(),player.getY(),32,32);

    for(Wall wall : walls) {

        Rectangle wall_rectangle = new Rectangle(wall.getX(), wall.getY(), 32,32);

        if (player_rectangle.intersects(wall_rectangle)) {
            Rectangle intersection = (Rectangle) player_rectangle.createIntersection(wall_rectangle);

            if (player.xspeed > 0) {
                player.x -= intersection.getWidth();
            }

            if (player.yspeed > 0) {
                player.y -= intersection.getHeight();
            }

            if (player.xspeed < 0) {
                player.x += intersection.getWidth();
            }

            if (player.yspeed < 0) {
                player.y += intersection.getHeight(); 
            }

            Print(Integer.toString(intersection.width) + ", " + Integer.toString(intersection.height));

        }

    }

}

通过这个$ C C $它正常工作，如果你是preSS一个按钮，但如果preSS向下和向左例如玩家将飞了出去，在一些随机的方向。

With this code it works fine if you are press one button but if press down and left for example the player will fly off in some random direction.

下面是地图类型的图片，我有：

Here is a picture of the types of maps I have:

推荐答案

您的主要问题是在假定播放器直接运行到墙上。考虑那里有一个壁矩形（100,100,32,32）和玩家是在（80,68,32,32）的情况。玩家被向下移动并到左边，所以player.xspeed＆其中; 0和player.yspeed> 0;说为玩家下一个位置（79,69,32,32）。该路口是那么（100,100,11,1）。

Your main problem is in assuming that the player is running directly into the wall. Consider the case where there is a wall rect (100,100,32,32) and the player is at (80,68,32,32). The player is moving down and to the left, so player.xspeed < 0 and player.yspeed > 0; say the next position for the player is (79,69,32,32). The intersection is then (100,100,11,1).

请注意，尽管玩家向左移动（以及向下）的壁实际上是播放器的右侧。该行：

Note that although the player is moving left (as well as down) the wall is actually to the right of the player. This line:

if (player.xspeed < 0) {
    player.x += intersection.getWidth();
}

...导致player.x在突然跳被设置为90。

... causes player.x to be set to 90 in a sudden jump.

有一件事情你可以做的是检查玩家的左侧是包含在路口，即

One thing you could do is check that the player's left-hand side was contained in the intersection, i.e.

if (player.xspeed < 0 && player.x >= intersection.x) {
    player.x += intersection.getWidth();
}

显然类似的事情，需要为其它方向也进行。

Obviously a similar thing needs to be done for the other directions too.

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