多线程启动订单 [英] multithread launching order

问题描述

我有4个线程来创建线程1，线程，thread3和thread4：

I have 4 threads to create thread1, thread2, thread3 and thread4:

pthread_create(thread1,NULL,thread_func1,NULL);
pthread_create(thread2,NULL,thread_func2,NULL);
pthread_create(thread3,NULL,thread_func3,NULL);
pthread_create(thread4,NULL,thread_func4,NULL);

寻找在调试，如在源$ C ​​$ C定义启动的线程的顺序是不一样的。
是否有启动线程与订单，我可以定义一个解决方案？

looking in the debug , The order of launched threads is not the same as defined in the source code. Are there a solution to launch the threads with an order that I could define?

推荐答案

在这里我使用的解决方案后，

here after the solution I used

#include <pthread.h>
#include <stdio.h>

static pthread_mutex_t mut = PTHREAD_MUTEX_INITIALIZER;
static pthread_cond_t cond = PTHREAD_COND_INITIALIZER;
static bool wait = TRUE;

void thread_sync() {
  pthread_mutex_lock(&mut);
  wait = FALSE;
  pthread_cond_signal(&cond);
  pthread_mutex_unlock(&mut);
}
void thread_wait_sync() {
  pthread_mutex_lock(&mut);
  if (wait==TRUE)
  {
      pthread_cond_wait(&cond,&mut);
  }
  wait = TRUE;
  pthread_mutex_unlock(&mut);
}

void *thread1(void *d) {
  thread_sync();
  while (1); // Rest of work happens whenever
  return NULL;
}

void *thread2(void *d) {
  thread_sync();
  while (1);
  return NULL;
}

void *thread3(void *d) {
  thread_sync();
  while (1);
  return NULL;
}

void *thread4(void *d) {
  while (1);
  return NULL;
}

int main() {
  pthread_t t1,t2,t3,t4;
  pthread_create(&t1, NULL, thread1, NULL);
  thread_wait_sync();
  pthread_create(&t2, NULL, thread2, NULL);
  thread_wait_sync();
  pthread_create(&t3, NULL, thread3, NULL);
  thread_wait_sync();
  pthread_create(&t4, NULL, thread4, NULL);
  while(1) {
    // some work
  }
}

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