获取的GeneralPath有序顶点 [英] Obtain ordered vertices of GeneralPath
问题描述
我怎样才能获得一个GeneralPath对象的顶点?看起来这应该是可能的,因为路径是从点(了lineTo,curveTo等)。构建
How can I obtain the vertices of a GeneralPath object? It seems like this should be possible, since the path is constructed from points (lineTo, curveTo, etc).
我想创建一个双[] []点数据(一个x / y坐标数组)。
I'm trying to create a double[][] of point data (an array of x/y coordinates).
推荐答案
您可以得到点从的的PathIterator
。
You can get the points back from the PathIterator
.
我不知道你的约束,但如果你的外形始终只有一个封闭的子路径,并具有唯一的直边(没有曲线),那么下面的工作:
I'm not sure what your constraints are, but if your shape always has just one closed subpath and has only straight edges (no curves) then the following will work:
static double[][] getPoints(Path2D path) {
List<double[]> pointList = new ArrayList<double[]>();
double[] coords = new double[6];
int numSubPaths = 0;
for (PathIterator pi = path.getPathIterator(null);
! pi.isDone();
pi.next()) {
switch (pi.currentSegment(coords)) {
case PathIterator.SEG_MOVETO:
pointList.add(Arrays.copyOf(coords, 2));
++ numSubPaths;
break;
case PathIterator.SEG_LINETO:
pointList.add(Arrays.copyOf(coords, 2));
break;
case PathIterator.SEG_CLOSE:
if (numSubPaths > 1) {
throw new IllegalArgumentException("Path contains multiple subpaths");
}
return pointList.toArray(new double[pointList.size()][]);
default:
throw new IllegalArgumentException("Path contains curves");
}
}
throw new IllegalArgumentException("Unclosed path");
}
如果您的路径可能包含的曲线,你可以使用<一个href="http://download.oracle.com/javase/6/docs/api/java/awt/geom/Path2D.html#getPathIterator%28java.awt.geom.AffineTransform,%20double%29"相对=nofollow> 的getPathIterator()的扁平化版本
。
If your path may contain curves, you can use the flattening version of getPathIterator()
.
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