返回id类型的二维数组c在Objective-C [英] Returning a 2D C array of type id in Objective-C

问题描述

我用我的iOS应用程序ID的二维数组c。是否有可能在一个Objective-C的方法返回此？作为一种替代解决方案，我试图返回一个指针二维数组c的整数，但我不能修改二维int数组。

   - （INT（*）[8] [8]）董事会（件*）件
{    INT（*布局）[8] [8] = malloc的（8 * 8 * sizeof的（INT））;    //不能修改布局二维数组c    返回布局;
}
 

我在Objective-C的一些经验，但没有在C.我会被不断地碰到用C二维数组的问题，比如我应该做一个二维阵列Objective-C类？什么是更典型的做法是iOS开发人员会使用？

解决方案

   - （INT **）板（片*）件
{    INT **布局=的malloc（8 * sizeof的为（int *））;
    的for（int i = 0; I＆LT; 8;我++）
       布局[I] = malloc的（8 * sizeof的（INT））;
    返回布局;
}
 

不要忘了在最后的记忆。此外，您还可以使用一维数组，像这样来访问它以类似的方式：

 的#define接入（数组，X，Y）阵列[Y * 8 + X]
 

还有现在在Objective-C的多维数组类下降，但你可以创建一个的NSArray 与其他的NSArray 的它的内部，或者，谷歌如果别人这样做（我记得至少有一个实现，但不记得它的名字）

I'm using a 2D C array of ids in my iOS app. Is it possible to return this in an objective-C method? As an alternative solution, I tried to return a pointer to a 2D C array of integers, but I cannot modify the 2D-int array.

- (int (*)[8][8])board:(Piece *)piece
{

    int (*layout)[8][8] = malloc(8 * 8 * sizeof(int));

    //Cannot modify layout 2D C array

    return layout;
}

I have some experience in Objective-C, but none in C. Am I likely to continually run into problems using C 2D arrays, such that I should make a 2D-Array Objective-C class? What is the more typical approach an iOS developer would use?

解决方案

- (int **)board:(Piece *)piece
{

    int **layout = malloc(8 * sizeof(int *));
    for(int i=0; i<8; i++)
       layout[i] = malloc(8 * sizeof(int));


    return layout;
}

Don't forget to free the memory in the end. Also, you could also use a one dimensional array and something like this to access it in a similar way:

#define access(array, x, y) array[y * 8 + x]

There is also now drop in multi-dimensional array class in Objective-C, but you could create a NSArray with other NSArray's inside of it, or, google if someone else did this (I remember at least one implementation but can't recall its name)

这篇关于返回id类型的二维数组c在Objective-C的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！