如何读取Linux的文件在C / C编程++权限 [英] How to read linux file permission programmatically in C/C++

问题描述

我怎么可以阅读编程，而不是使用LSLinux的文件权限，然后解析结果。

How can I read linux file permission programmatically instead using "ls" then parse the result.

推荐答案

的 STAT（2）系统调用返回 struct stat中包含 ST_MODE 成员。这是模式比特的ls -l <​​/ code>显示。

The stat(2) system call returns a struct stat that contains a st_mode member. This is the mode bits that ls -l displays.

在我的系统中， 2人统计页说：

   The following flags are defined for the st_mode field:

   S_IFMT     0170000   bitmask for the file type bitfields
   S_IFSOCK   0140000   socket
   S_IFLNK    0120000   symbolic link
   S_IFREG    0100000   regular file
   S_IFBLK    0060000   block device
   S_IFDIR    0040000   directory
   S_IFCHR    0020000   character device
   S_IFIFO    0010000   FIFO
   S_ISUID    0004000   set UID bit
   S_ISGID    0002000   set-group-ID bit (see below)
   S_ISVTX    0001000   sticky bit (see below)
   S_IRWXU    00700     mask for file owner permissions
   S_IRUSR    00400     owner has read permission
   S_IWUSR    00200     owner has write permission
   S_IXUSR    00100     owner has execute permission
   S_IRWXG    00070     mask for group permissions
   S_IRGRP    00040     group has read permission
   S_IWGRP    00020     group has write permission
   S_IXGRP    00010     group has execute permission
   S_IRWXO    00007     mask for permissions for others (not in group)
   S_IROTH    00004     others have read permission
   S_IWOTH    00002     others have write permission
   S_IXOTH    00001     others have execute permission

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