反正很快打破了字为字符目标C数组？ [英] Anyway to quickly break a word into an array of characters in objective c?

问题描述

例如：的NSString * strWord =英语;

结果的NSArray会是这样的：简体中文

The result NSArray would be something like: e n g l i s h

我觉得是可能做到这一点。

I think is possible to do it with

[NSString的componentSeparatedByCharacter：somecharacter]，但我不知道性格是什么...

[NSString componentSeparatedByCharacter:somecharacter], but I don't know what that character is...

我写了这样的事情，提取的字符：

I wrote something like this to extract the character:

NSString *character;
for (int i=0; i<[strWord length]; i++) {
    character = [strWord substringWithRange:NSMakeRange(i, 1)];
}

感谢您的帮助！

推荐答案

如果你需要一一列举，并支持iOS 4.0或更高版本，可以使用

If you need to enumerate them and support iOS 4.0 or later, you could use

[strWord enumerateSubstringsInRange:NSMakeRange(0, [strWord length])
                            options:NSStringEnumerationByComposedCharacterSequences
                         usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop){
    // substring here contains each character in turn
}];

您也可以只使用字符 -getCharacters复制到缓冲区：范围：如果你实际上并不需要他们作为一个NSArray。或者你可以只遍历字符串（使用块的方法，或致电 -characterAtIndex：反复，或复制出整个缓冲区，并遍历了），并构建您自己的数组。

You could also just copy the characters into a buffer using -getCharacters:range: if you don't actually need them as an NSArray. Or you could just iterate over the string (using the block method, or by calling -characterAtIndex: repeatedly, or by copying out the entire buffer and iterating over that) and construct your own array.

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