转换一个C-ctyle字符串连接codeD作为字符数组Java的String [英] Converting a C-ctyle string encoded as a character array to a Java String

问题描述

我有一个C风格的字符串连接codeD作为Java的字符数组，但我想这个数组转换成Java的String。我试图使用匹配的构造函数调用，

I have a C-style string encoded as an array of characters in Java, but I would like to convert this array to a Java String. I tried using the matching constructor call,

String toRet = new String(new char[]{'B','A','D','\0', 'G', 'A', 'R', 'B', 'A', 'G', 'E'});
System.out.println(Arrays.toString(toRet.toCharArray()));

但结果是不正确的，事实上奇怪手推车。下面是上面code输出：

But the result is incorrect, and in fact oddly buggy. Here's what the above code outputs:

[B, A, D,

这就是我想要的。

[B, A, D]

我在openJdk6 Ubuntu上运行。我没有测试过的其他虚拟机上面的code。

I'm running on openJdk6 on Ubuntu. I haven't tested the above code on other VM's.

推荐答案

有没有必要到这里涉及到一个字符串。只需复制到一个新的数组，它是一个字符比你输入数组短。使用此任务的方法是 Arrays.copyOf 。

There is no need for a String to get involved here. Just copy into a new array that is one char shorter than your input array. The method to use for this task is Arrays.copyOf.

原因你的输出是越野车是因为在Java字符串有无关空终止符。您code的第一行创建一个字符串，它的最后一个字符是空字符。

The reason your output is buggy is because strings in Java have nothing to do with null-terminators. Your first line of code creates a string whose last character is the null-character.

如果您有垃圾继空字符，你可以使用新的String（inputArray），然后找到空字符与字符串。的indexOf（'\\ 0'）和使用，在 String.substring 操作切出不需要的部分。然而，这将是简单还是（从时间/空间复杂度的角度），只是迭代这个数组找到空字符，然后用 Arrays.copyOf 与指数作为分界点。

If you have garbage following the null-char, you can use new String(inputArray), then find the null-char with String.indexOf('\0') and use that in a String.substring operation to cut out the unneeded part. However, it would be still simpler (from the time/space complexity perspective) to just iterate over the array to locate the null-char and then use Arrays.copyOf with that index as cutoff point.

这篇关于转换一个C-ctyle字符串连接codeD作为字符数组Java的String的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！