Python扩展：符号（S）没有发现建筑x86_64的错误 [英] Python extension: symbol(s) not found for architecture x86_64 error

问题描述

我想要写在C Python扩展。我在Mac上工作，我花了code从这里：

I want to write a python extension in c. I work on Mac, I took a code from here:

#include <Python.h>

static PyObject* say_hello(PyObject* self, PyObject* args)
{
    const char* name;

    if (!PyArg_ParseTuple(args, "s", &name))
        return NULL;

    printf("Hello %s!\n", name);

    Py_RETURN_NONE;
}

static PyMethodDef HelloMethods[] =
{
     {"say_hello", say_hello, METH_VARARGS, "Greet somebody."},
     {NULL, NULL, 0, NULL}
};

PyMODINIT_FUNC

inithello(void)
{
     (void) Py_InitModule("hello", HelloMethods);
}

我编译：

gcc -c -o py_module.o py_module.c -I/Library/Frameworks/Python.framework/Versions/2.7/include/python2.7/
gcc -o py_module py_module.o -I/Library/Frameworks/Python.framework/Versions/2.7/include/python2.7/ -lm

但我得到这个错误：

But I get this error:

Undefined symbols for architecture x86_64:
  "_PyArg_ParseTuple", referenced from:
      _say_hello in py_module.o
  "_Py_InitModule4_64", referenced from:
      _inithello in py_module.o
  "__Py_NoneStruct", referenced from:
      _say_hello in py_module.o
  "_main", referenced from:
      start in crt1.10.6.o
ld: symbol(s) not found for architecture x86_64
collect2: ld returned 1 exit status
make: *** [py_module] Error 1

如何产生Python不支持 X86_64 架构？

推荐答案

两件事情：

• 您需要将您的扩展链接作为共享对象（你试图链接可执行文件，这就是为什么连接器正在寻找的main（））


• 您需要对Python的静态库（ -lpython ）链接。

• You need to link your extension as a shared object (you're attempting to link an executable, which is why the linker is looking for main());
• You need to link against the Python static library (-lpython).

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