可在不SQLITE prepare INSERT语句，C API [英] Can not prepare INSERT statement in SQLITE, C API

问题描述

  /* DATABASE INIT */

ret = sqlite3_open_v2(dbfile, &DB, SQLITE_OPEN_READWRITE | SQLITE_OPEN_CREATE, NULL);

if (SQLITE_OK != ret) {
    printf("Could not open database.\n");
    exit(1);
}

const char* zSql = "INSERT INTO abc VALUES (?)";
ret = sqlite3_prepare_v2(sites[DB, zSql, strlen(zSql), &s, NULL);

if (SQLITE_OK != ret) {
    printf("Could not compile statement '%s', got %d.\n", zSql, ret);
    exit(1);
}

好了，你去那里。怎么了？ sqlite3_ prepare_v2总是失败。

Well, there you go. What's wrong? sqlite3_prepare_v2 always fails.

更新：
我试过到目前为止的建议，但没有雪茄。
我创造了我能想到的最简单的情况下，用一个模式：

Update: I tried the suggestions so far, but no cigar. I created the simplest case I could think of, with a schema:

CREATE TABLE abc(a INTEGER);

而C code作为以上，仍然不能正常工作，得到无法编译陈述
得到了回报code 26这显然意味着 SQLITE_NOTADB 。因此，似乎我的数据库文件是不是... ...一个数据库文件。奇怪，我将不得不考虑这一点。

And the C code as above, still does not work, gets 'Could not compile statement' got return code 26 which apparently means SQLITE_NOTADB. So it seems my database file is not... a database file. Strange, I will have to look into this.

SQLite的CLI接受该文件，并能显示模式，如果我用使用.dump命令。

The sqlite CLI accepts the file and can show the schema if I use the ".dump" command.

我是从data.db到data.sqlite更改的数据库文件名。现在我得到的1回报code，SQLITE_ERROR代替。

I changed the database file name from "data.db" to "data.sqlite". Now I get a return code of 1, SQLITE_ERROR, instead.

的更新：的
我访问了错误的文件，AKA 用户错误。
接受，在我的未经编辑的提问时指出语法错误的答案之一。

Update: I was accessing the wrong file, AKA user error. Accepting one of the answers that pointed out a syntax error in my unedited question.

推荐答案

我想你应该尝试

const char* zSql = 
    "INSERT INTO abc (moderation_status, phonenumber, email) VALUES(?,?,?)";

假设 moderation_status PHONENUMBER 和电子邮件是名在表中的字段。

assuming moderation_status phonenumber and email are the names of the fields in your table.

或

const char* zSql = "INSERT INTO abc VALUES(?,?,?)";

的？是这里的参数将被插入的占位符。

The ? is the placeholder for where the arguments will be inserted.

这篇关于可在不SQLITE prepare INSERT语句，C API的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！