寻找指向的argv [0]这样我就可以改变它 [英] Finding pointer to argv[0] so I can change it

问题描述

在Solaris上我有一个指向的argv [0] 与 getexecname ，然后我可以的memcpy 在该位置。 （每<一个href=\"http://stackoverflow.com/questions/1023306/finding-current-executables-path-without-proc-self-exe/1024937#1024937\">Finding没有的/ proc /自/ EXE 当期可执行的路径）

On Solaris I got a pointer to argv[0] with getexecname and then I can memcpy at that location. (per Finding current executable's path without /proc/self/exe)

我想知道如何得到一个指向的argv [0] 在Linux中我做了的readlink 在的/ proc /自/ EXE ，但它不给我一个指针。

I was wondering how to get a pointer to argv[0] in Linux I did readlink on /proc/self/exe but it doesn't give me a pointer to it.

感谢

推荐答案

有关的readlink ，把你自己的缓冲区。您分配一个缓冲区，在一个指针传递给它，而的readlink 将有保存结果：

For readlink, Bring Your Own Buffer. You allocate a buffer, pass in a pointer to it, and readlink will store the results there:

#include <unistd.h>
#include <linux/limits.h>

int main() {
  char buffer[PATH_MAX];

  int size = readlink("/proc/self/exe", buffer, sizeof(buffer));
  buffer[size] = '\0';

  // buffer is now the char* holding the filename

  printf("The executable is %s\n", buffer);
}

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