获取的属性名作为字符串 [英] Get name of property as a string

问题描述

（请参见下面的解决方案我创建使用我接受的答案）

(See below solution I created using the answer I accepted)

我试图改善涉及一些反思code的可维护性。该应用程序有一个.NET远程接口暴露（除其他事项外）被称为执行访问不包括在其公布的远程接口的应用程序的部分方法。

I'm trying to improve the maintainability of some code involving reflection. The app has a .NET Remoting interface exposing (among other things) a method called Execute for accessing parts of the app not included in its published remote interface.

下面是该应用如何指定的属性（在本例中静态的），其意思是访问通过执行：

Here is how the app designates properties (a static one in this example) which are meant to be accessible via Execute:

RemoteMgr.ExposeProperty("SomeSecret", typeof(SomeClass), "SomeProperty");

因此​​，一个远程用户可以拨打电话：

So a remote user could call:

string response = remoteObject.Execute("SomeSecret");

和应用程序将使用反射来找到SomeClass.SomeProperty并返回其值作为一个字符串。

and the app would use reflection to find SomeClass.SomeProperty and return its value as a string.

不幸的是，如果有人重命名SomeProperty而忘记改变ExposeProperty（）的第三PARM，它打破了这种机制。

Unfortunately, if someone renames SomeProperty and forgets to change the 3rd parm of ExposeProperty(), it breaks this mechanism.

我需要等价的：

SomeClass.SomeProperty.GetTheNameOfThisPropertyAsAString()

在ExposeProperty第三PARM这样的重构工具将采取重命名的注意使用。

to use as the 3rd parm in ExposeProperty so refactoring tools would take care of renames.

有没有办法做到这一点？先谢谢了。

Is there a way to do this? Thanks in advance.

好吧，这里是我结束了创建（根据我选择了答案，他所引用的问题）：

Okay, here's what I ended up creating (based upon the answer I selected and the question he referenced):

// <summary>
// Get the name of a static or instance property from a property access lambda.
// </summary>
// <typeparam name="T">Type of the property</typeparam>
// <param name="propertyLambda">lambda expression of the form: '() => Class.Property' or '() => object.Property'</param>
// <returns>The name of the property</returns>
public string GetPropertyName<T>(Expression<Func<T>> propertyLambda)
{
    var me = propertyLambda.Body as MemberExpression;

    if (me == null)
    {
        throw new ArgumentException("You must pass a lambda of the form: '() => Class.Property' or '() => object.Property'");
    }

    return me.Member.Name;
 }

用法：

// Static Property
string name = GetPropertyName(() => SomeClass.SomeProperty);

// Instance Property
string name = GetPropertyName(() => someObject.SomeProperty);

现在同此凉能力，​​它的时间来简化ExposeProperty方法。抛光的门把手是危险的工作...

Now with this cool capability, it's time to simplify the ExposeProperty method. Polishing doorknobs is dangerous work...

谢谢大家。

推荐答案

从这里使用GetMemberInfo：<一href=\"http://stackoverflow.com/questions/671968/retrieving-property-name-from-lambda-ex$p$pssion\">http://stackoverflow.com/questions/671968/retrieving-property-name-from-lambda-ex$p$pssion你可以做这样的事情：

Using GetMemberInfo from here: http://stackoverflow.com/questions/671968/retrieving-property-name-from-lambda-expression you can do something like this:

RemoteMgr.ExposeProperty（（）=＆GT; SomeClass.SomeProperty）

public class SomeClass
{
    public static string SomeProperty
    {
        get { return "Foo"; }
    }
}

public class RemoteMgr
{
    public static void ExposeProperty<T>(Expression<Func<T>> property)
    {
        var expression = GetMemberInfo(property);
        string path = string.Concat(expression.Member.DeclaringType.FullName,
            ".", expression.Member.Name);
        // Do ExposeProperty work here...
    }
}

public class Program
{
    public static void Main()
    {
        RemoteMgr.ExposeProperty("SomeSecret", () => SomeClass.SomeProperty);
    }
}

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