创建自IList℃的逗号分隔的列表;串＆GT;或IEnumerable的＆LT;串GT; [英] Creating a comma separated list from IList<string> or IEnumerable<string>

问题描述

什么是创建一个的IList＆LT字符串值的逗号分隔的列表最彻底的方法;串＆GT; 或的IEnumerable＆LT;串＆GT; ？

的string.join（...）在字符串操作[] 等都可以用繁琐的工作当类型，如的IList＆LT;串＆GT; 或的IEnumerable＆LT;字符串方式＆gt; 不能很容易地转换成字符串数组

String.Join(...) operates on a string[] so can be cumbersome to work with when types such as IList<string> or IEnumerable<string> cannot easily be converted into a string array.

推荐答案

.NET 4 +

IList<string> strings = new List<string>{"1","2","testing"};
string joined = string.Join(",", strings);

详情＆安培; pre .NET 4.0解决方案

的IEnumerable＆LT;串＆GT; 可以被转换成一个字符串数组的非常的轻松与LINQ（.NET 3.5）：

IEnumerable<string> can be converted into a string array very easily with LINQ (.NET 3.5):

IEnumerable<string> strings = ...;
string[] array = strings.ToArray();

这是很容易，如果你需要编写相当于辅助方法：

It's easy enough to write the equivalent helper method if you need to:

public static T[] ToArray(IEnumerable<T> source)
{
    return new List<T>(source).ToArray();
}

然后调用它是这样的：

Then call it like this:

IEnumerable<string> strings = ...;
string[] array = Helpers.ToArray(strings);

您可以调用的string.join 。当然，你不这样做的有无的使用一个辅助方法：

You can then call string.Join. Of course, you don't have to use a helper method:

// C# 3 and .NET 3.5 way:
string joined = string.Join(",", strings.ToArray());
// C# 2 and .NET 2.0 way:
string joined = string.Join(",", new List<string>(strings).ToArray());

后者是有点拗口，但：）

The latter is a bit of a mouthful though :)

这很可能是做到这一点的最简单的方法，而且相当高性能以及 - 大约有性能正是等，包括其它问题，（但不限于）<一href=\"http://stackoverflow.com/questions/219519/whats-the-c-method-syntax-for-converting-an-array-to-a-simple-string\">this 之一。

This is likely to be the simplest way to do it, and quite performant as well - there are other questions about exactly what the performance is like, including (but not limited to) this one.

由于.NET 4.0，也有 更多可用的重载串。加入 ，所以实际上你可以这样写：

As of .NET 4.0, there are more overloads available in string.Join, so you can actually just write:

string joined = string.Join(",", strings);

简单多了：）

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