如何显示从C#文件的属性对话框? [英] How do I display a file's Properties dialog from C#?
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问题描述
如何通过一个按钮打开一个文件的属性对话框
how to open an file's Properties dialog by a button
private void button_Click(object sender, EventArgs e)
{
string path = @"C:\Users\test\Documents\tes.text";
// how to open this propertie
}
感谢您。
例如,如果想在系统属性
For example if want the System properties
Process.Start("sysdm.cpl");
但我如何获得的属性对话框的文件路径?
But how do i get the Properties dialog for a file path?
推荐答案
解决办法是:
using System.Runtime.InteropServices;
[DllImport("shell32.dll", CharSet = CharSet.Auto)]
static extern bool ShellExecuteEx(ref SHELLEXECUTEINFO lpExecInfo);
[StructLayout(LayoutKind.Sequential, CharSet = CharSet.Auto)]
public struct SHELLEXECUTEINFO
{
public int cbSize;
public uint fMask;
public IntPtr hwnd;
[MarshalAs(UnmanagedType.LPTStr)]
public string lpVerb;
[MarshalAs(UnmanagedType.LPTStr)]
public string lpFile;
[MarshalAs(UnmanagedType.LPTStr)]
public string lpParameters;
[MarshalAs(UnmanagedType.LPTStr)]
public string lpDirectory;
public int nShow;
public IntPtr hInstApp;
public IntPtr lpIDList;
[MarshalAs(UnmanagedType.LPTStr)]
public string lpClass;
public IntPtr hkeyClass;
public uint dwHotKey;
public IntPtr hIcon;
public IntPtr hProcess;
}
private const int SW_SHOW = 5;
private const uint SEE_MASK_INVOKEIDLIST = 12;
public static bool ShowFileProperties(string Filename)
{
SHELLEXECUTEINFO info = new SHELLEXECUTEINFO();
info.cbSize = System.Runtime.InteropServices.Marshal.SizeOf(info);
info.lpVerb = "properties";
info.lpFile = Filename;
info.nShow = SW_SHOW;
info.fMask = SEE_MASK_INVOKEIDLIST;
return ShellExecuteEx(ref info);
}
// button click
private void button1_Click(object sender, EventArgs e)
{
string path = @"C:\Users\test\Documents\test.text";
ShowFileProperties(path);
}
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