修改字符数组,修改的部分显示出来向后 [英] Modifying a character array, the modified part shows up backwards
问题描述
我刚开始学习汇编,我试图修改一个字符数组。
I have just started learning assembly, and I am trying to modify a character array.
这是我的组装code:
This is my assembly code:
.data
data byte 'Five', 0
.code
Asm proc
lea rax, data
mov dword ptr[rax], 'Four'
ret
Asm endp
end
和我的C ++ code:
And my C++ code:
#include <stdio.h>
#include <conio.h>
// external function
extern "C" char* Asm();
// main function
int main()
{
printf(Asm());
_getch();
}
当我注释掉 MOV DWORD PTR [RAX],四
,其结果是在控制台打印:十一五的。但是,上述code取消注释,结果是ruoF的,而不是什么,我希望它是,这显然是的四的。
When I comment out mov dword ptr[rax], 'Four'
, the result is that the console prints: "Five". But, with the above code uncommented, the result is "ruoF", instead of what I expected it to be, which is obviously "Four".
这是怎么回事?我怎样才能获得文本的正确方向输出,无需做一些廉价的解决方法是这样的:<?code> MOV DWORD PTR [RAX],ruoF
Why is this happening? How can I get the text to output in the correct direction without having to do some cheap workaround like this: mov dword ptr[rax], 'ruoF'
?
推荐答案
您可以使用:
mov ebx,'Four'
bswap ebx
mov [rax],ebx
或者,在支持 movbe
英特尔凌动处理器(可与确认CPUID
):
Or, on Intel Atom processors that support movbe
(can be confirmed with cpuid
):
mov ebx,'Four'
movbe [rax],ebx
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