LINQ到XML新手：移动节点从一个节点到另一个 [英] LINQ to XML Newbie: Moving Nodes From One Node To Another

问题描述

您好！

我有一个包含以下内容的对象的XElement：

I have an XElement object that contains the following:

<Root>
    <SubSections>
        <SubSection id="A">
            <Foo id="1">
                <Bar />
                <Bar />
                <Bar />
            </Foo>
            <Foo id="2">
                <Bar />
                <Bar />
            </Foo>
            <Foo id="3">
                <Bar />
            </Foo>
        </SubSection>
        <SubSection id="B">
            <Foo id="4">
                <Bar />
                <Bar />
                <Bar />
            </Foo>
            <Foo id="5">
                <Bar />
                <Bar />
            </Foo>
         </SubSection>
        <SubSection id="C">

        </SubSection>
    </SubSections>
</Root>

我想Foo的2和3移动到款而C的ID，这样的结果是：

I'd like to move Foo's 2 and 3 to the SubSection with the id of "C" such that the result is:

<Root>
    <SubSections>
        <SubSection id="A">
            <Foo id="1">
                <Bar />
                <Bar />
                <Bar />
            </Foo>
        </SubSection>
        <SubSection id="B">
            <Foo id="4">
                <Bar />
                <Bar />
                <Bar />
            </Foo>
            <Foo id="5">
                <Bar />
                <Bar />
            </Foo>
        </SubSection>
        <SubSection id="C">
            <Foo id="2">
                <Bar />
                <Bar />
            </Foo>
            <Foo id="3">
                <Bar />
            </Foo>
        </SubSection>
    </SubSections>
</Root>

什么是去移动富段2的最佳途径，3到C款？

What's the best way to go about moving Foo sections "2" and "3" to the "C" SubSection?

推荐答案

您需要得到美孚第2和第3像查询：

You need to get Foo sections 2 and 3 with a query like:

var foos = from xelem in root.Descendants("Foo")
           where xelem.Attribute("id").Value == "2" || xelem.Attribute("id").Value == "3"
           select xelem;

然后遍历该列表，并从他们的父母将其删除

And then iterate that list and remove them from their parents with

xelem.Remove();

然后把它们添加到正确的节点有：

Then just add them to the correct node with:

parentElem.Add(xelem);

第一个查询将让你两部分然后删除和添加每一个到树的正确的位置。

The first query will get you both sections then remove and add each one to the correct place on the tree.

下面是一个完整的解决方案：

Here's a complete solution:

var foos = (from xElem in xDoc.Root.Descendants("Foo")
                   where xElem.Attribute("id").Value == "2" || xElem.Attribute("id").Value == "3"
                   select xElem).ToList();

        var newParentElem = (from xElem in xDoc.Root.Descendants("SubSection")
                            where xElem.Attribute("id").Value == "C"
                            select xElem).Single();

        foreach(var xElem in foos)
        {
            xElem.Remove();
            newParentElem.Add(xElem);
        }

在您应该XDOC有正确的树。

After that your xDoc should have the correct tree.

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