与多个客户端TCP服务器 [英] TCP server with multiple Clients

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本文介绍了与多个客户端TCP服务器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我工作的TCP服务器/客户端应用程序。

我的问题是:

我的服务器应用程序启动一个新的线程,并阻止它,直到连接被接受
该listenforClient方法

但我怎么能管理连接当多个客户端连接到我的服务器,他们要求不同的东西的同时如何管理客户端1获取信息的需求,并同客户端2。

它的多线程,因此多个客户端可以连接,但我怎么可以处理该请求。
我不想把一切都在1比的方法会是什么。

由于提前

 私人无效serverstart()
    {
        this.tcplistener =新的TcpListener(IPAddress.Any,49151);
        this.listenThread =新主题(新的ThreadStart(ListenForClients));
        this.listenThread.Start();
    }    私人无效ListenForClients()
    {
        this.tcplistener.Start();        而(真)
        {
            //块,直到客户端已连接到服务器
            TcpClient的客户= this.tcplistener.AcceptTcpClient();
            //这里是:第一,发送hello客户端的消息
            //
            ////////////////////////////////////////////////// /            //创建一个线程来处理通信
            //与连接的客户端
            螺纹clientThread =新主题(新ParameterizedThreadStart(HandleClientComm));            clientThread.Start(客户端);
        }
    }    私人无效HandleClientComm(对象客户端)
    {
        的TcpClient的TcpClient =(TcpClient的)客户端;
        的NetworkStream clientStream = tcpClient.GetStream();        字节[]消息=新的字节[4096];
        INT读取动作;        而(真)
        {
            读取动作= 0;            尝试
            {
                //阻塞,直到客户端发送一个消息
                读取动作= clientStream.Read(消息,0,4096);
            }
            抓住
            {
                //套接字错误发生
                打破;
            }            如果(读取动作== 0)
            {
                //客户端已与服务器断开连接
                打破;
            }            //消息已被成功地接收到
            ASCIIEncoding EN codeR =新ASCIIEncoding();            bufferincmessage = EN coder.GetString(消息0,读取动作);
            如果(System.Text.RegularEx pressions.Regex.IsMatch(bufferincmessage,Properties.Settings.Default.REQLogin,System.Text.RegularEx pressions.RegexOptions.IgnoreCase))
            {
                bufferincmessageresult = bufferincmessage.Split('^');
                nickname_Cl = bufferincmessageresult [1];
                password_Cl = bufferincmessageresult [2];
                getuserdata_db();
                登录();                字节[]缓冲= EN coder.GetBytes(inlogmessage);                clientStream.Write(缓冲液,0,buffer.Length);
                clientStream.Flush();
            }
        }
    }


解决方案

您客户端将在不同的线程调度,所以他们不会相交。
你只需要添加类似您的信息将被处理DispatchMethod。

 使用System.Text.RegularEx pressions;
...如果(Regex.IsMatch(bufferincmessage,Properties.Settings.Default.REQLogin,RegexOptions.IgnoreCase))
{
    ...
}
否则,如果(Regex.IsMatch(bufferincmessage,/ *你的一些的Command * / RegexOptions.IgnoreCase))
{
    ...
}
否则,如果(Regex.IsMatch(bufferincmessage,/ *你的一些的Command * / RegexOptions.IgnoreCase))
{
    ...
}

I am working on TCP server/client application.

My question is:

My server application starts a new thread and blocks it until connection is accepted the listenforClient method

But how can I manage the connections when multiple Clients are connected to my server and they request different things at the same time how can i manage that client 1 gets info its need and same for client 2.

It's multithreaded, so multiple Clients can connect but how can i process the request. I don't want to put everything in 1 method what than would.

Thanks in Advance

private void serverstart()
    {
        this.tcplistener = new TcpListener(IPAddress.Any, 49151);
        this.listenThread = new Thread(new ThreadStart(ListenForClients));
        this.listenThread.Start();
    }

    private void ListenForClients()
    {
        this.tcplistener.Start();

        while (true)
        {
            //blocks until a client has connected to the server
            TcpClient client = this.tcplistener.AcceptTcpClient();


            // here was first an message that send hello client
            //
            ///////////////////////////////////////////////////

            //create a thread to handle communication
            //with connected client
            Thread clientThread = new Thread(new ParameterizedThreadStart(HandleClientComm));

            clientThread.Start(client);
        }
    }

    private void HandleClientComm(object client)
    {
        TcpClient tcpClient = (TcpClient)client;
        NetworkStream clientStream = tcpClient.GetStream();

        byte[] message = new byte[4096];
        int bytesRead;

        while (true)
        {
            bytesRead = 0;

            try
            {
                //blocks until a client sends a message
                bytesRead = clientStream.Read(message, 0, 4096);
            }
            catch
            {
                //a socket error has occured
                break;
            }

            if (bytesRead == 0)
            {
                //the client has disconnected from the server
                break;
            }

            //message has successfully been received
            ASCIIEncoding encoder = new ASCIIEncoding();

            bufferincmessage = encoder.GetString(message, 0, bytesRead);


            if (System.Text.RegularExpressions.Regex.IsMatch(bufferincmessage, Properties.Settings.Default.REQLogin, System.Text.RegularExpressions.RegexOptions.IgnoreCase))
            {
                bufferincmessageresult = bufferincmessage.Split('^');
                nickname_Cl = bufferincmessageresult[1];
                password_Cl = bufferincmessageresult[2];
                getuserdata_db();
                login();

                byte[] buffer = encoder.GetBytes(inlogmessage);

                clientStream.Write(buffer, 0, buffer.Length);
                clientStream.Flush();
            }


        }
    }

解决方案

Your client will be dispatched in different threads, so they will not intersect. You just need to add something like "DispatchMethod" where your messages will be processed.

using System.Text.RegularExpressions;
...

if (Regex.IsMatch(bufferincmessage, Properties.Settings.Default.REQLogin, RegexOptions.IgnoreCase))
{
    ...
}
else if (Regex.IsMatch(bufferincmessage, /*some of your command1*/, RegexOptions.IgnoreCase))
{
    ...
}
else if (Regex.IsMatch(bufferincmessage, /*some of your command1*/, RegexOptions.IgnoreCase))
{
    ...
}

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