如何转换JSON数组，列出在C＃中的对象 [英] How to convert Json array to list of objects in c#

问题描述

我有JSON字符串像下面

I have Json string like below

 {
"JsonValues":{

        "id": "MyID",

         "values": {
            "value1":{
                "id": "100",
                "diaplayName": "MyValue1"
            },
            "value2":{
                "id": "200",
                "diaplayName": "MyValue2"
            }
       }
}
}

我想转换JSON字符串以下类

I want to convert Json string to below classes

  class ValueSet
   {
    [JsonProperty("id")]
    public string id
    {
        get;
        set;
    }
    [JsonProperty("values")]
    public List<Value> values
    {
        get;
        set;
    }
  }

class Value
{
    public string id
    {
        get;
        set;
    }
    public string DiaplayName
    {
        get;
        set;
    }
}

我的反序列化code是

My deserialization code is

JavaScriptSerializer js = new JavaScriptSerializer();
        StreamReader sr = new StreamReader(@"ValueSetJsonString.txt");
        string jsonString = sr.ReadToEnd();
        var items = JsonConvert.DeserializeObject<ValueSet>(jsonString);

但我序列化之后得到空值，我怎么能解决这个问题？

But I am getting null values after serialization, How i can solve this?

推荐答案

正如其他人已经指出的那样，你没有得到你所期望的结果的原因是因为你的JSON不匹配类结构，你试图反序列化成。要么你需要改变你的JSON或更改类。既然别人已经展示了如何改变JSON，我会采取相反的做法在这里。

As others have already pointed out, the reason you are not getting the results you expect is because your JSON does not match the class structure that you are trying to deserialize into. You either need to change your JSON or change your classes. Since others have already shown how to change the JSON, I will take the opposite approach here.

要匹配你在你的问题张贴的JSON，你的类应该像低于定义。请注意，我已经做了以下修改：

To match the JSON you posted in your question, your classes should be defined like those below. Notice I've made the following changes:

1. 我添加相应的外部对象的包装类在你的JSON。


2. 我改变了值从列表＆LT的 ValueSet 类物业;价值＆GT; 到词典＆LT;字符串值＆GT; 因为值在你的JSON属性包含对象，而不是一个数组。


3. 我增加了一些额外 [JsonProperty] 属性在JSON对象匹配的属性名称。

1. I added a Wrapper class corresponding to the outer object in your JSON.
2. I changed the Values property of the ValueSet class from a List<Value> to a Dictionary<string, Value> since the values property in your JSON contains an object, not an array.
3. I added some additional [JsonProperty] attributes to match the property names in your JSON objects.

类定义：

class Wrapper
{
    [JsonProperty("JsonValues")]
    public ValueSet ValueSet { get; set; }
}

class ValueSet
{
    [JsonProperty("id")]
    public string Id { get; set; }
    [JsonProperty("values")]
    public Dictionary<string, Value> Values { get; set; }
}

class Value
{
    [JsonProperty("id")]
    public string Id { get; set; }
    [JsonProperty("diaplayName")]
    public string DisplayName { get; set; }
}

您需要反序列化到包装类，而不是 ValueSet 类。然后，您可以得到 ValueSet 从包装。

You need to deserialize into the Wrapper class, not the ValueSet class. You can then get the ValueSet from the Wrapper.

var valueSet = JsonConvert.DeserializeObject<Wrapper>(jsonString).ValueSet;

下面是一个工作程序来演示：

Here is a working program to demonstrate:

class Program
{
    static void Main(string[] args)
    {
        string jsonString = @"
        {
            ""JsonValues"": {
                ""id"": ""MyID"",
                ""values"": {
                    ""value1"": {
                        ""id"": ""100"",
                        ""diaplayName"": ""MyValue1""
                    },
                    ""value2"": {
                        ""id"": ""200"",
                        ""diaplayName"": ""MyValue2""
                    }
                }
            }
        }";

        var valueSet = JsonConvert.DeserializeObject<Wrapper>(jsonString).ValueSet;

        Console.WriteLine("id: " + valueSet.Id);
        foreach (KeyValuePair<string, Value> kvp in valueSet.Values)
        {
            Console.WriteLine(kvp.Key + " id: " + kvp.Value.Id);
            Console.WriteLine(kvp.Key + " name: " + kvp.Value.DisplayName);
        }
    }
}

这里是输出：

id: MyID
value1 id: 100
value1 name: MyValue1
value2 id: 200
value2 name: MyValue2

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