BigInteger的解析至八进制字符串转换？ [英] BigInteger Parse Octal String?

问题描述

在Java中，我能做到

In Java, I could do

//Parsing Octal String
BigInteger b = new BigInteger("16304103460644701340432043410021040424210140423204",8);

接着，当我高兴格式化

Then format it as I pleased

b.toString(2); //2 for binary
b.toString(10); //10 for decimal
b.toString(16); //16 for hexadecimal

C＃的的BigInteger 提供上面显示的格式设置功能，但我似乎无法找到一种方法来解析BIIIG（大于64位无符号）八进制的值。

C#'s BigInteger offers the formatting capabilities shown above but I can't seem to find a way to parse BIIIG (greater than 64 bit, unsigned) Octal values.

推荐答案

这可能不是最有效的解决方案，但如果表现不是很重要，您可以构造的BigInteger 手动：

This may not be the most efficient solution, but if performance is not a priority, you can construct the BigInteger manually:

string s = "16304103460644701340432043410021040424210140423204";
BigInteger bi = s.Aggregate(new BigInteger(), (b, c) => b * 8 + c - '0');

上面的解决方案还适用于任何碱不大于10;只需更换 8 在上面的code。与您所需的基准。

The above solution also works for any base not greater than 10; just replace the 8 in the above code with your required base.

修改：对于十六进制数字，你应该使用解析方法。 prePEND与 0 如果您的号码应该是PTED因为即使它的第一个字符是正间$ P $ 8 - ˚F

Edit: For hexadecimal numbers, you should use the Parse method. Prepend with 0 if your number should be interpreted as positive even if its first character is 8–F.

string s = "0F20051C5E45F4FD68F8E58905A133BCA";
BigInteger bi = BigInteger.Parse(s, NumberStyles.HexNumber);

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