年数和月在Microsoft Access计算时代（2010年） [英] calculating age in years and months in Microsoft Access (2010)

问题描述

我有两个字段（体检和出生日期的日期）。我计算了年龄岁（出生物理应试日期（日期）/365.25）。我想要做的是计算年，月独立场年龄。我不知道这是否可以用code ++ BUILDER或某种方式来完成。

I have two fields (Date of Physical Exam and Date of Birth). I calculated the age in years((Date of Physical Exam- Date of Birth)/365.25). What I want to do is calculate age in years and months in separate field. I am not sure if it can be done using code builder or some way.

推荐答案

而则DateDiff（）的功能似乎是计算年龄的合理选择，这不幸的是不计算数量的完全的年两个日期之间已经过去了几个月。例如，假设一个婴儿出生于2014年12月31日，并精确地检测48小时后，于1月2日，2015年也就是

While the DateDiff() function seems like the logical choice for calculating ages, it unfortunately does not calculate the number of full years or months that have elapsed between two dates. For example, say that a baby was born on December 31, 2014, and was examined exactly 48 hours later, on January 2, 2015. That is,

DateOfBirth = DateSerial(2014, 12, 31)
DateOfExam = DateSerial(2015, 1, 2)

如果我们只是用则DateDiff（）来计算考试，我们会得到的时间，以年和月她的年龄

If we simply used DateDiff() to calculate her "age" in years and months at the time of the exam we would get

?DateDiff("yyyy", DateOfBirth, DateOfExam)
 1 
?DateDiff("m", DateOfBirth, DateOfExam)
 1 

那么，我们就报告说，宝宝1岁1个月大的时候，确实她只是2的天的老人。

适当年龄计算中，需要为比更复杂。下面的VBA函数将计算时代的年数和月，返回像2年1个月的字符串：

Proper age calculations need to be more sophisticated than that. The following VBA function will calculate the "age" in years and months, returning a string like "2 years and 1 month":

Public Function AgeInYearsAndMonths(StartDate As Variant, EndDate As Variant) As Variant
    Dim Date1 As Date, Date2 As Date
    Dim mm1 As Integer, dd1 As Integer, mm2 As Integer, dd2 As Integer
    Dim ageYears As Integer, ageMonths As Integer, rtn As Variant
    rtn = Null
    If Not (IsNull(StartDate) Or IsNull(EndDate)) Then
        If StartDate <= EndDate Then
            Date1 = StartDate
            Date2 = EndDate
        Else
            Date1 = EndDate
            Date2 = StartDate
        End If
        mm1 = Month(Date1)
        dd1 = Day(Date1)
        mm2 = Month(Date2)
        dd2 = Day(Date2)
        ageYears = DateDiff("yyyy", Date1, Date2)
        If (mm1 > mm2) Or (mm1 = mm2 And dd1 > dd2) Then
            ageYears = ageYears - 1
        End If
        ageMonths = DateDiff("m", Date1, Date2) Mod 12
        If dd1 > dd2 Then
            If ageMonths = 0 Then
                ageMonths = 12
            End If
            ageMonths = ageMonths - 1
        End If
        If ageYears = 0 And ageMonths = 0 Then
            rtn = "less than 1 month"
        Else
            rtn = ageYears & " year" & IIf(ageYears = 1, "", "s") & " and " & ageMonths & " month" & IIf(ageMonths = 1, "", "s")
        End If
    End If
    AgeInYearsAndMonths = rtn
End Function

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