在C＃中填充0-9之间，潮头随机数的数组 [英] filling a array with uniqe random numbers between 0-9 in c#

问题描述

我要填写我的数组在C＃
0-9独特的随机数我试试这个功能：

I want to fill my array with unique random numbers between 0-9 in c# I try this function:

    IEnumerable<int> UniqueRandom(int minInclusive, int maxInclusive)
    {
        List<int> candidates = new List<int>();
        for (int i = minInclusive; i <= maxInclusive; i++)
        {
            candidates.Add(i);
        }
        Random rnd = new Random();
        while (candidates.Count > 1)
        {
            int index = rnd.Next(candidates.Count);
            yield return candidates[index];
            candidates.RemoveAt(index);
        }
    }

和我使用它是这样的：

for (int i = 0; i < 3; i++)
{
    page[i] = UniqueRandom(0, 9);
}

但我得到了错误：

But I got error :

Cannot implicitly convert type 'System.Collections.Generic.IEnumerable<int>' to 'int'

我也添加了这个名字空间：

I also added this name space:

using System.Collections.Generic;

我只是不知道我怎么能转换函数输出为int ...请帮助我...谢谢...

I just don't know how I can convert the function output to int... please help me... thank you...

推荐答案

您是好得多做这样的事情，使用的费 - 耶茨洗牌：

You're much better off doing something like this, using a Fischer-Yates shuffle:

public static void Shuffle<T>(this Random rng, IList<T> list)  
{  
    int n = list.Count;  
    while (n > 1) {  
        n--;  
        int k = rng.Next(n + 1);  
        T value = list[k];  
        list[k] = list[n];  
        list[n] = value;  
    }  
}

的用法：的

var numbers = Enumerable.Range(0, 10).ToList(); // 0-9 inclusive
var rng = new Random();
rng.Shuffle(numbers);
int[] page = numbers.Take(3).ToArray();

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