动作 - 获取当前函数的名称 [英] Actionscript - Obtain the name of the current function

问题描述

我想从该函数内部得到一个函数的名称。例如：

I want to get the name of a function from inside that function. e.g.:

function blah() {
    //I want to get the string "blah" here, from the function's name
}

或者至少在功能对象？

Or at least the Function object?

推荐答案

使用的 arguments.callee的得到引用当前函数。

Use arguments.callee to get a reference to the current function.

我要获取函数名，这是一个有点棘手：所有功能都被视为方法闭包（的code片可被传递作为参数），所以他们没有自己的参考一个封闭类的类型，它们也没有一个现名。

I you want to get the function name, it is a bit trickier: All functions are treated as method closures (pieces of code which can be passed around as an argument), so they do not own a reference to an enclosing class type, nor do they have a "current name".

不过，如果（和的只有的IF）的方法是公共的，和你想从一个实例对象的类声明包含的方法来获取方法的名称，你可以使用的不如describeType ：

However, if (and only if) the method is public, and you want to get the method name from the class declaration of an instance object containing the method, you can use describeType:

public function someFunction() : void {
    var callee:Function = arguments.callee;
    trace (getFunctionName(callee, this)); // ==> someFunction
}

private function someOtherFunction() : void {
    var callee:Function = arguments.callee;
    trace (getFunctionName(callee, this)); // ==> not found
}

private function getFunctionName (callee:Function, parent:Object):String {
    for each ( var m:XML in describeType(parent)..method) {
        if ( parent[m.@name] == callee) return m.@name;
    }
    return "not found";
}

请注意，当你调用这个是行不通的 someFunction（）从构造函数，因为该对象未完全实例化 - 不如describeType（本） 在构造函数会导致编译错误。

Note that this would not work when you call someFunction() from a constructor, because the object is not fully instantiated - describeType(this) in a constructor would cause a compilation error.

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