如何使用表达式设置属性值? [英] How to set property value using Expressions?
问题描述
公共静态无效SetPropertyValue(对象的目标,字符串作为propName,对象的值)
:考虑下面的方法 {
VAR propInfo = target.GetType()的getProperty(作为propName,
BindingFlags.Instance | BindingFlags.Public | BindingFlags.NonPublic可| BindingFlags.DeclaredOnly)。
如果(propInfo == NULL)
抛出新ArgumentOutOfRangeException(作为propName,没有目标找到物业);
,否则
propInfo.SetValue(目标,价值,NULL);
}
您会如何去写它的表情启用相当于无需在传递对目标额外的参数?
为什么这样做,而不是设置属性直接我能听到你说。例如,假设我们有一个具有公共的getter但私人二传手属性下面的类:
公共类客户
{
公共字符串名称{搞定;私人集;}
公共字符串名称{;设置;}
}
我希望能够调用:
VAR myCustomerInstance =新客户();
SetPropertyValue<客户>(卡斯特= GT; myCustomerInstance.Title,先生);
现在这里是一些示例代码。
公共静态无效SetPropertyValue< T>(表达式来; Func键< T,对象>> memberLamda,对象的值)
{
MemberExpression memberSelectorExpression;
VAR selectorExpression = memberLamda.Body;
VAR castExpression = selectorExpression为UnaryExpression;
如果(castExpression!= NULL)
memberSelectorExpression = castExpression.Operand为MemberExpression;
,否则
memberSelectorExpression = memberLamda.Body为MemberExpression;
//我如何获得myCustomerInstance的值,这样我可以调用的SetValue在把它当作一个参数?是否有可能
}
任何指针?
您能欺骗,让生活更容易使用的扩展方法:
公共静态类LambdaExtensions
{
公共静态无效SetPropertyValue< T>(这件T目标,表达< Func键< T,对象>> memberLamda,对象值)
{
VAR memberSelectorExpression = memberLamda.Body为MemberExpression;
如果(!memberSelectorExpression = NULL)
{
VAR财产= memberSelectorExpression.Member为的PropertyInfo;
如果(财产!= NULL)
{
property.SetValue(目标,价值,NULL);
}
}
}
}
和那么:
VAR myCustomerInstance =新客户();
myCustomerInstance.SetPropertyValue(C => c.Title,先生);
之所以这样是比较容易的,因为你已经在其上调用扩展方法的对象。另外,lambda表达式是不封闭的简单成员表达式。在你原来的例子目标是在封闭拍摄的,它可能是一个有点虽然拿到底层目标和的PropertyInfo
。
Given the following method:
public static void SetPropertyValue(object target, string propName, object value)
{
var propInfo = target.GetType().GetProperty(propName,
BindingFlags.Instance | BindingFlags.Public | BindingFlags.NonPublic | BindingFlags.DeclaredOnly);
if (propInfo == null)
throw new ArgumentOutOfRangeException("propName", "Property not found on target");
else
propInfo.SetValue(target, value, null);
}
How would you go about writing it's expression enabled equivalent without needing to pass in an extra parameter for target?
Why do this instead of setting the property directly I can hear you say. For example suppose we have the following class with a property that has a public getter but private setter:
public class Customer
{
public string Title {get; private set;}
public string Name {get; set;}
}
I would like to be able to call:
var myCustomerInstance = new Customer();
SetPropertyValue<Customer>(cust => myCustomerInstance.Title, "Mr");
Now here is some sample code.
public static void SetPropertyValue<T>(Expression<Func<T, Object>> memberLamda , object value)
{
MemberExpression memberSelectorExpression;
var selectorExpression = memberLamda.Body;
var castExpression = selectorExpression as UnaryExpression;
if (castExpression != null)
memberSelectorExpression = castExpression.Operand as MemberExpression;
else
memberSelectorExpression = memberLamda.Body as MemberExpression;
// How do I get the value of myCustomerInstance so that I can invoke SetValue passing it in as a param? Is it possible
}
Any pointers?
You could cheat and make life easier with an extension method:
public static class LambdaExtensions
{
public static void SetPropertyValue<T>(this T target, Expression<Func<T, object>> memberLamda, object value)
{
var memberSelectorExpression = memberLamda.Body as MemberExpression;
if (memberSelectorExpression != null)
{
var property = memberSelectorExpression.Member as PropertyInfo;
if (property != null)
{
property.SetValue(target, value, null);
}
}
}
}
and then:
var myCustomerInstance = new Customer();
myCustomerInstance.SetPropertyValue(c => c.Title, "Mr");
The reason why this is easier is because you already have the target on which the extension method is invoked. Also the lambda expression is a simple member expression without closures. In your original example the target is captured in a closure and it could be a bit though to get to the underlying target and PropertyInfo
.
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